我编写了一个python脚本,以独特的方式为OpenGL着色器组合图像。问题是我有大量非常大的地图,需要很长时间才能处理。有没有办法以更快的方式写这个?
import numpy as np
map_data = {}
image_data = {}
for map_postfix in names:
file_name = inputRoot + '-' + map_postfix + resolution + '.png'
print 'Loading ' + file_name
image_data[map_postfix] = Image.open(file_name, 'r')
map_data[map_postfix] = image_data[map_postfix].load()
color = mapData['ColorOnly']
ambient = mapData['AmbientLight']
shine = mapData['Shininess']
width = imageData['ColorOnly'].size[0]
height = imageData['ColorOnly'].size[1]
arr = np.zeros((height, width, 4), dtype=int)
for i in range(width):
for j in range(height):
ambient_mod = ambient[i,j][0] / 255.0
arr[j, i, :] = [color[i,j][0] * ambient_mod , color[i,j][1] * ambient_mod , color[i,j][2] * ambient_mod , shine[i,j][0]]
print 'Converting Color Map to image'
return Image.fromarray(arr.astype(np.uint8))
这只是大量批处理过程的一个示例,所以如果有更快的方法来迭代和修改图像文件,我会更感兴趣。几乎所有的时间都花在了嵌套循环上,而不是加载和保存。
答案 0 :(得分:2)
矢量化代码示例 - 在timeit
或zmq.Stopwatch()
报告有22.14秒>>加速0.1624秒!
虽然您的代码似乎只是在RGBA [x,y]上循环,但让我展示一个" 矢量化 " - 代码的解析,这得益于numpy
矩阵操作实用程序(忘记RGB / YUV操作(最初基于OpenCV而不是PIL),但重新使用矢量化语法方法以避免 - 循环并使其适应您的微积分。错误的操作顺序可能会使您的处理时间增加一倍。
并使用测试/优化/重新测试循环来加速。
对于测试,如果timeit
分辨率足够,请使用标准python [msec]
。
如果您需要进入zmq.StopWatch()
解决方案,请选择[usec]
。
# Vectorised-code example, to see the syntax & principles
# do not mind another order of RGB->BRG layers
# it has been OpenCV traditional convention
# it has no other meaning in this demo of VECTORISED code
def get_YUV_U_Cb_Rec709_BRG_frame( brgFRAME ): # For the Rec. 709 primaries used in gamma-corrected sRGB, fast, VECTORISED MUL/ADD CODE
out = numpy.zeros( brgFRAME.shape[0:2] )
out -= 0.09991 / 255 * brgFRAME[:,:,1] # // Red
out -= 0.33601 / 255 * brgFRAME[:,:,2] # // Green
out += 0.436 / 255 * brgFRAME[:,:,0] # // Blue
return out
# normalise to <0.0 - 1.0> before vectorised MUL/ADD, saves [usec] ...
# on 480x640 [px] faster goes about 2.2 [msec] instead of 5.4 [msec]
在您的情况下,使用dtype = numpy.int
,猜测MUL
首先ambient[:,:,0]
最后DIV
标准化arr[:,:,:3] /= 255
# test if this goes even faster once saving the vectorised overhead on matrix DIV
arr[:,:,0] = color[:,:,0] * ambient[:,:,0] / 255 # MUL remains INT, shall precede DIV
arr[:,:,1] = color[:,:,1] * ambient[:,:,0] / 255 #
arr[:,:,2] = color[:,:,2] * ambient[:,:,0] / 255 #
arr[:,:,3] = shine[:,:,0] # STO alpha
那么你的算法看起来怎么样?
人们不必拥有彼得杰克逊令人印象深刻的预算和时间一旦计划,跨越并执行了超过3年在新西兰机库进行的巨大数字运算,一群SGI工作站过度拥挤,因为他正在制作&#34; 指环王&#34;完全数字母版制作装配线,通过逐帧像素操作,认识到大规模生产管道中的毫秒和微秒甚至纳秒只是重要。
因此,深呼吸,测试并重新测试,以便将您的真实图像处理性能优化到您的项目所需的水平。
希望这可以帮助你:
# OPTIONAL for performance testing -------------# ||||||||||||||||||||||||||||||||
from zmq import Stopwatch # _MICROSECOND_ timer
# # timer-resolution step ~ 21 nsec
# # Yes, NANOSECOND-s
# OPTIONAL for performance testing -------------# ||||||||||||||||||||||||||||||||
arr = np.zeros( ( height, width, 4 ), dtype = int )
aStopWatch = zmq.Stopwatch() # ||||||||||||||||||||||||||||||||
# /\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\# <<< your original code segment
# aStopWatch.start() # |||||||||||||__.start
# for i in range( width ):
# for j in range( height ):
# ambient_mod = ambient[i,j][0] / 255.0
# arr[j, i, :] = [ color[i,j][0] * ambient_mod, \
# color[i,j][1] * ambient_mod, \
# color[i,j][2] * ambient_mod, \
# shine[i,j][0] \
# ]
# usec_for = aStopWatch.stop() # |||||||||||||__.stop
# print 'Converting Color Map to image'
# print ' FOR processing took ', usec_for, ' [usec]'
# /\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\# <<< proposed alternative
aStopWatch.start() # |||||||||||||__.start
# reduced numpy broadcasting one dimension less # ref. comments below
arr[:,:, 0] = color[:,:,0] * ambient[:,:,0] # MUL ambient[0] * [{R}]
arr[:,:, 1] = color[:,:,1] * ambient[:,:,0] # MUL ambient[0] * [{G}]
arr[:,:, 2] = color[:,:,2] * ambient[:,:,0] # MUL ambient[0] * [{B}]
arr[:,:,:3] /= 255 # DIV 255 to normalise
arr[:,:, 3] = shine[:,:,0] # STO shine[ 0] in [3]
usec_Vector = aStopWatch.stop() # |||||||||||||__.stop
print 'Converting Color Map to image'
print ' Vectorised processing took ', usec_Vector, ' [usec]'
return Image.fromarray( arr.astype( np.uint8 ) )