Question

我想使用具有以下结构的jackson从JSON字符串创建对象

public class A {
    private int id;
    private B b;

    public A() {
        id = 5;
        b = new B(10, 20);
    }

    public int getId() {
        return this.id;
    }

    public B getB() {
        return b;
    }
}
public class B {
    private int first;
    private int last;

    public B(int first, int last) {
        this.first = first;
        this.last = last;
    }
}

如果我使用以下代码进行序列化/反序列化，则在反序列化步骤中失败注意：我不想更改代码结构并为类B添加默认的空构造函数或使用JsonProperty注释。因为A类负责创建B内部我需要一些方法来防止jackson在尝试从json字符串反序列化A类时实例化一个新的B来覆盖A类的b属性

    A a = new A();
    ObjectMapper b = new ObjectMapper();
    b.configure(Feature.FAIL_ON_EMPTY_BEANS, false);
    String jsonString = b.writeValueAsString(a);
    // jsonString = {"id":5,"b":{}} which is desirable in serialization but it fails in deserialization with the following statement.
    A readValue = b.readValue(jsonString, A.class);

Answer 1

@JsonIgnore到您的私人B类变量。

IE：

@JsonIgnore
private B b;

如何防止jackson在反序列化中实例化新对象

1 个答案: