Question

我有以下表结构和数据

DriverName CarType      StartTime                  EndTime
---------- -------      ---------                  --------
DriverA    Honda        2014-09-29 14:32:03        2014-09-29 14:48:09
DriverA    Honda        2014-09-29 12:32:03        2014-09-29 14:32:09
DriverA    Honda        2014-09-29 10:32:03        2014-09-29 14:32:09

DriverA    Toyota        2014-09-29 10:32:03       2014-09-29 10:34:09
DriverA    Toyota        2014-09-29 9:32:03        2014-09-29 9:39:09
DriverA    Toyota        2014-09-29 8:32:03        2014-09-29 8:52:09

如何以秒/分钟/小时

获得最差的最佳和平均时间

DriverName  CarType     Worst                        Best      
---------- --------     ------                       -----     
DriverA     Honda       04:00:06 (4 hrs 6 seconds)    00:04:06 (4 minutes 3 seconds)
DriverA     Toyota      00:20:06 (4 hrs 6 seconds)    00:2:06 (20 minutes 3 seconds)

Answer 1

为了得到最好和最差，你会想要在开始时间和结束时间之间获得日期差异，然后分别获得最小值或最大值，然后对于平均值，你基本上可以做同样的但是使用平均值功能。最后你会想要分类CarType和（我认为）驱动程序这里是一个例子：

修改

有人指出DATEDIFF没有按照我的预期运作，它会在几天内明确返回差异，我已经更新了查询以使用TIMEDIFF代替，我还添加了使用TIME_TO_SEC()函数直接在几秒钟内提供输出。

SELECT DriverName, CarType, MAX(TIME_TO_SEC(TIMEDIFF(EndTime,StartTime))) AS 'Worst', MIN(TIME_TO_SEC(TIMEDIFF(EndTime,StartTime))) AS 'Best', AVG(TIME_TO_SEC(TIMEDIFF(EndTime,StartTime))) AS 'Average' GROUP BY DriverName, CarType

Answer 2

您可能想要使用timestampdiff()

select DriverName, CarType,
       min(timestampdiff(second, StartTime, EndTime)) as Best,
       max(timestampdiff(second, StartTime, EndTime)) as Worst
from followingtable ft
group by DriverName, CarType;

如果要将值显示为时间格式：

select DriverName, CarType,
       date_format(cast(0 as datetime) + interval min(timestampdiff(second, StartTime, EndTime,)) second,
                   '%H:%m:%d) as Best,
       date_format(cast(0 as datetime) + interval max(timestampdiff(second, StartTime, EndTime)) second,
                   '%H:%m:%d') as Worst
from followingtable ft
group by DriverName, CarType;

如何查找表中行的最小和最大时差

2 个答案: