我有类似的东西将表格中的数据插入我的MySQL表格。我在插入中使用select语句有效吗?请赐教。
if(isset($_POST['date']) && isset($_POST['docName']) && isset($_POST['docSpec']) && isset($_POST['time']) && isset($_POST['symptoms']) )
{
$nameOfUser = $_COOKIE['userlogin'];
$docName = $_POST['docName'];
$date = $_POST['date'];
$symptoms = $_POST['symptoms'];
$time = date('H:i:s',strtotime($_POST['time']));
$id = mt_rand(1000,9999); //generate random appointment id
$insertQuery = "insert into appointment values
($id,(select doctorid from doctors where doctorName like '$docName' ),
$date,$symptoms,
(select patientid from patient where patientFName like '$nameOfUser'), $time)";
if(mysqli_query($conn,$insertQuery)===true)
{
echo "<script>alert('success');</script>";
}
else
{
die('Invalid query: ' . mysql_error());
$message .= 'Whole query: ' . $query;
die($message);
}
}
它表示无效查询。 insert语句中的列已按正确顺序排列。有谁可以帮助我?
答案 0 :(得分:0)
您必须指定要插入的列 -
insert into appointment (col1, col2, col3, ...) values
($id,(select doctorid from doctors where doctorName like '$docName' ), $date,$symptoms,(select patientid from patient where patientFName like '$nameOfUser'),$time)";
看起来你有6列。
编辑:这种语法可能有助于清理 -
$insertQuery = "INSERT INTO `appointment` (`col1`, `col2`, `col3`,`col4`,`col5`,`col6`) ";
$insertQuery .= "VALUES (";
$insertQuery .= "'" . $id . "'";
$insertQuery .= ", '" . "(SELECT `doctorid` FROM `doctors` WHERE `doctorName` LIKE '%" . $docName . "%')" . "'";
$insertQuery .= ", '" . $date . "'";
$insertQuery .= ", '" . $symptoms . "'";
$insertQuery .= ", '" . "(SELECT `patientid` FROM `patient` WHERE `patientName` LIKE '%" . $nameOfUser . "%')" . "'";
$insertQuery .= ", '" . $time . "'";
$insertQuery .= ")";
您还使用了LIKE而没有给它机会找到其他元素,因为您没有使用通配符。