如何设置始终显示的警报?

时间:2014-09-29 12:36:34

标签: java android broadcastreceiver alerts batterymanager

现在,我只想在用户访问应用时获得某种电池状态指示。例如,如果设备已插入,则设备应该说充电和它的电平。如果设备已拔下,则不应显示任何内容。如果设备未充电且电池电量不足,则应显示电池电量不足指示。

我已经设置了大部分代码,但问题是,例如,如果我运行应用程序并且设备已插入,屏幕上会显示充电指示。如果我拔下设备,则不再显示充电但如果我重新插入设备,则仍然无法再显示充电。当设备插入或拔出,​​电池电量不足或电量不足时,应始终显示电池警报。应始终显示信息更改。

所以这是我的广播接收器:

  private BroadcastReceiver mBatInfoReceiver = new BroadcastReceiver()  {

        @Override
        public void onReceive(Context arg0, Intent intent) {

            //Battery level
            int level = intent.getIntExtra("level", 0);

            //Plugged in Status
            int plugged = intent.getIntExtra(BatteryManager.EXTRA_PLUGGED, -1);

            //Battery Status
            int status = intent.getIntExtra(BatteryManager.EXTRA_STATUS, -1);

            //If the device is charging or contains a full status, it's charging
            boolean isCharging = status == BatteryManager.BATTERY_STATUS_CHARGING ||
                    status == BatteryManager.BATTERY_STATUS_FULL;

            //If the device isCharging and plugged in, then show that the battery is charging
            TextView batteryTextView = ((TextView) findViewById(R.id.charging));
            TextView batteryLowTextView = ((TextView) findViewById(R.id.low_battery));
            ImageView batteryLowImageView= ((ImageView) findViewById(R.id.low_battery_icon));
            ImageView batteryImageView =((ImageView) findViewById(R.id.charging_battery_icon));

            if (isCharging && plugged == BatteryManager.BATTERY_PLUGGED_AC || plugged == BatteryManager.BATTERY_PLUGGED_USB) {


                //Gets the 'last synced' string and sets to datetime of the last sync
                Resources resources = context.getResources();
                String chargingString = String.format(resources.getString(R.string.charging), level);

                //Dynamically sets the value of the battery level
                batteryLowTextView.setVisibility(TextView.INVISIBLE);
                batteryLowImageView.setVisibility(ImageView.INVISIBLE);
                batteryTextView.setText(chargingString + "%");

            } else if (level < LOW_BATTERY_LEVEL && !isCharging) {

                Resources resources = context.getResources();
                String lowBatteryString = String.format(resources.getString(R.string.low_battery));

                batteryTextView.setVisibility(TextView.INVISIBLE);
                batteryImageView.setVisibility(ImageView.INVISIBLE);
                batteryLowTextView.setText(lowBatteryString);

            } else if (!isCharging && level > LOW_BATTERY_LEVEL) {

                //do nothing
                batteryTextView.setVisibility(TextView.GONE);
                batteryImageView.setVisibility(ImageView.GONE);

            }

        }

    };

在我的OnCreate方法中,我调用

 //calls registerReceiver to receive the broadcast for the state of battery
            this.registerReceiver(this.mBatInfoReceiver,new
                    IntentFilter(Intent.ACTION_BATTERY_CHANGED));

所以,我想知道我做错了什么?是bools吗?

2 个答案:

答案 0 :(得分:5)

  1. 你的if-then-else逻辑有很多漏洞(并且有@Vikram提到的问题)。这可能导致接收器最终无所事事。尝试简化逻辑以删除所有漏洞。
  2. 更新文本视图时,还必须记住首先使其(及其图像视图)可见。
  3. 这是if-then-else逻辑的替代品:

            if (isCharging) {
    
                //Gets the 'last synced' string and sets to datetime of the last sync
                Resources resources = context.getResources();
                String chargingString = String.format(resources.getString(R.string.charging), level);
    
                //Dynamically sets the value of the battery level
                batteryLowTextView.setVisibility(TextView.INVISIBLE);
                batteryLowImageView.setVisibility(ImageView.INVISIBLE);
                batteryTextView.setText(chargingString + "%");
                batteryTextView.setVisibility(TextView.VISIBLE);
                batteryImageView.setVisibility(ImageView.VISIBLE);
    
            } else if (level <= LOW_BATTERY_LEVEL) {
    
                Resources resources = context.getResources();
                String lowBatteryString = String.format(resources.getString(R.string.low_battery));
    
                batteryTextView.setVisibility(TextView.INVISIBLE);
                batteryImageView.setVisibility(ImageView.INVISIBLE);
                batteryLowTextView.setText(lowBatteryString);
                batteryLowTextView.setVisibility(TextView.VISIBLE);
                batteryLowImageView.setVisibility(ImageView.VISIBLE);
    
            } else {
    
                //show nothing
                batteryTextView.setVisibility(TextView.GONE);
                batteryImageView.setVisibility(ImageView.GONE);
                batteryLowTextView.setVisibility(TextView.GONE);
                batteryLowImageView.setVisibility(ImageView.GONE);
            }
    

答案 1 :(得分:2)

AND isCharging BatteryManager.BATTERY_PLUGGED_AC此处:

if (isCharging && plugged == BatteryManager.BATTERY_PLUGGED_AC || plugged == BatteryManager.BATTERY_PLUGGED_USB) 

您需要OR BatteryManager个控件和AND结果isCharging,如:

if (isCharging && 
   (plugged == BatteryManager.BATTERY_PLUGGED_AC || plugged == BatteryManager.BATTERY_PLUGGED_USB))

如果您需要知道设备是否基本上插入 AC USB ,您可以使用此方法。但是,设备可以插入BATTERY_PLUGGED_WIRELESS。另一件事是,你的isCharging变量已经涵盖了你想要找到的内容:

(plugged == BatteryManager.BATTERY_PLUGGED_AC || plugged == BatteryManager.BATTERY_PLUGGED_USB)

我强烈建议您阅读this page并调试以控制您使用的变量的值。