Selenium自动化不适用于弹出窗口

时间:2014-09-29 11:29:32

标签: java selenium-webdriver

我正在使用Selenium 2.x WebDriver来实现java项目的自动化。 当自动化进行时,它会到达一个页面,当单击提交按钮时,会出现“弹出窗口”,无法继续进行自动化。

代码

public void writeSite(WebDriver driver, ZoneTest zone) throws BiffException, InterruptedException, IOException

    //Creates a new zone for testing

    General.elementClick_xpath(driver, Locators.siteMenuDropBoxXpath);
    General.waitToLoad(General.WAIT_MIN);
    General.elementClick_xpath(driver, Locators.viewSitesButtonXpath);
    General.elementClick_xpath(driver, Locators.viewDataPointDetailsXpath);
    General.waitToLoad(General.WAIT_AVG);

    General.elementClick_xpath(driver, Locators.addZoneXpath);

    General.waitToLoad(General.WAIT_AVG);

    General.inputTextFieldEnter_Id(driver, "name", zone.zoneName);
    General.inputTextFieldEnter_Id(driver, "description",zone.zoneDescription );
    General.inputTextFieldEnter_Id(driver, "urlExtension", zone.urlExtension);
    General.inputTextFieldEnter_Id(driver, "timeSpentThreshold", zone.thresholdTime);
    General.inputTextFieldEnter_Id(driver, "tuningNumber", zone.tuningNumber);

   **General.elementClick_xpath(driver, Locators.createZoneSubmitXpath);**

   //Here a new pop up window apppears. And the following codes 3 lines doesnt work.

    General.inputTextFieldEnter_Id(driver, "active", zone.act);
    General.inputTextFieldEnter_Id(driver, "userid", zone.uid);
    General.elementClick_xpath(driver, Locators.SubmitXpath)
}


public class General 
{
  public static final long WAIT_MICRO = 500;
  public static final long WAIT_MIN = 2000;
  public static final long WAIT_AVG = 5000;
  public static final long WAIT_MAX = 5500;
  public static String baseUrl ="";


  //Method to wait  
  public static void waitToLoad(long milliSeconds) throws InterruptedException {
     Thread.sleep(milliSeconds);
  }

     // Method to load the Url taken from the config.property file

  public static void loadBaseUrl(WebDriver driver){
     baseUrl = PropertyUtility.getProperty("Baseurl");
     driver.get(baseUrl);
     driver.manage().timeouts().implicitlyWait(20, TimeUnit.SECONDS);
  }

  public static void inputTextFieldEnter_xpath(WebDriver driver, String LocatorId, String ValueToBeEntered) throws InterruptedException {       
     System.out.println("Log in user name_inputTextField_outside if: "+ ValueToBeEntered);
     WebElement inputTextField = driver.findElement(By.xpath(LocatorId));
     General.waitUntilElementVisible(driver, LocatorId);
     inputFieldClear_xpath(driver,LocatorId);
     inputTextField.sendKeys(ValueToBeEntered);     
}

如何将视图切换到新的弹出窗口?

3 个答案:

答案 0 :(得分:8)

如果要在弹出窗口中执行任何操作,可以使用WebDriver逻辑来选择弹出窗口。

driver.switchTo().window("<window name>");

答案 1 :(得分:1)

如果出现任何弹出窗口,则您必须切换到该窗口。因为除非您提及该窗口名称,否则它将无法自动识别新窗口。

语法:set ws = driver.get windowshandles();

    Iterator itr=ws.iterate();

    String W1=(String)itr.next();

    String W2=(String)itr.next();

driver.switchTo()窗口(W1);

(或)

driver.switchTo()窗口(W2);

(或) ......

答案 2 :(得分:0)

您需要先切换该窗口,然后按照您的需要进行操作。您必须使用以下命令来切换窗口。

driver.switchTo().window("Window ID");

您可以使用以下命令获取所有已打开的窗口唯一ID。

Set<String> windows = driver.getWindowHandles();

在您的情况下,请使用以下代码作为切换窗口。

String vBaseWindowHandle = driver.getWindowHandle();
    Set<String> windows = driver.getWindowHandles();

    for(String temp : windows)
    {
        driver.switchTo().window(temp);
    }

    // Do code for new window

    driver.close();     
    driver.switchTo().window(vBaseWindowHandle);

有关如何处理窗口和弹出窗口的更多信息,请转到下面的URL https://trickyautomationworld.blogspot.in/2018/03/how-to-handle-windows-in-selenium.html https://trickyautomationworld.blogspot.in/2018/03/how-to-handle-popup-in-selenium.html