Question

我有以下数组：

var source = [
            { "DistributorId": 1, "DistributorName": "Distributor 01", "PriceListId": 1, "Year": 2014, "Month": 9 },
            { "DistributorId": 1, "DistributorName": "Distributor 01", "PriceListId": 2, "Year": 2014, "Month": 10 },
            { "DistributorId": 2, "DistributorName": "Distributor 02", "PriceListId": 3, "Year": 2014, "Month": 10 },
            { "DistributorId": 3, "DistributorName": "Distributor 03", "PriceListId": 4, "Year": 2014, "Month": 9 },
            { "DistributorId": 3, "DistributorName": "Distributor 03", "PriceListId": 5, "Year": 2014, "Month": 10 }
        ];

我想使用linq.js将这些数组分组为两个字段＆＃34; DistributorId＆＃34;和＆＃34; DistributorName＆＃34; 得到以下结果：

var des =
        [
            {
                "DistributorId": 1,
                "DistributorName": "Distributor 01",
                "PriceLists":
                [
                    { "Year": 2014, "Month": 9 },
                    { "Year": 2014, "Month": 10 }
                ]
            },
            {
                "DistributorId": 2,
                "DistributorName": "Distributor 02",
                "PriceLists":
                [
                    { "Year": 2014, "Month": 10 }
                ]
            },
            {
                "DistributorId": 3,
                "DistributorName": "Distributor 03",
                "PriceLists":
                [
                    { "Year": 2014, "Month": 9 },
                    { "Year": 2014, "Month": 10 }
                ]
            }
        ];

Answer 1

你想要的群组重载如下：

// Overload:function(keySelector,elementSelector,resultSelector,compareSelector)

首先，您需要一个密钥，它是分销商ID和名称的组合。然后收集具有相同分销商ID和名称的所有年份和月份。当然的结果和比较关键对象的方法（作为字符串的属性是实现它的简单方法）。

var query = Enumerable.from(data)
    .groupBy(
        "{ Id: $.DistributorId, Name: $.DistributorName }",
        "{ Year: $.Year, Month: $.Month }",
        "{ DistributorId: $.Id, DistributorName: $.Name, PriceLists: $$.toArray() }",
        "String($.Id) + $.Name"
    )
    .toArray();

请注意，我使用的是linq.js 3.x名称：使用lowerCamelCase的方法。对旧版本更改为UpperCamelCase。

Answer 2

这应该可以解决问题：

var source = [
    { "DistributorId": 1, "DistributorName": "Distributor 01", "PriceListId": 1, "Year": 2014, "Month": 9 },
    { "DistributorId": 1, "DistributorName": "Distributor 01", "PriceListId": 2, "Year": 2014, "Month": 10 },
    { "DistributorId": 2, "DistributorName": "Distributor 02", "PriceListId": 3, "Year": 2014, "Month": 10 },
    { "DistributorId": 3, "DistributorName": "Distributor 03", "PriceListId": 4, "Year": 2014, "Month": 9 },
    { "DistributorId": 3, "DistributorName": "Distributor 03", "PriceListId": 5, "Year": 2014, "Month": 10 }
];

var dest = [];
source.map(function(current){
    var id = current.DistributorId - 1;
    dest[id] = dest[id] || {
        "DistributorId": current.DistributorId,
        "DistributorName": current.DistributorName,
        "PriceLists": []
    };
    dest[id].PriceLists.push({ "Year": current.Year, "Month": current.Month });
})

Linq.js：Group By two properties（fields）

2 个答案: