Question

我需要RegEx命令来获取所有没有包含“filewatch”的作业名称的行。任何帮助将不胜感激！感谢。

STATUS: FAILURE         JOB: i3-imds-dcp-pd-bo1-05-ftpfilewatcher
STATUS: FAILURE         JOB: i3-cur-atmrec-pd-TD_FTP_Forecast_File_Del_M_Su
ALARM: JOBFAILURE       JOB: i3-cur-atmrec-pd-TD_FTP_Forecast_File_Del_M_Su
STATUS: FAILURE         JOB: i3-sss-system-heartbeat
ALARM: JOBFAILURE       JOB: i3-sss-system-heartbeat
STATUS: FAILURE         JOB: i3-chq-cspo-pd-batch-daily-renametable-fileok
STATUS: FAILURE         JOB: i3-chq-cspo-pd-batch-daily-renametable-file
ALARM: JOBFAILURE       JOB: i3-chq-cspo-pd-batch-daily-renametable-fileok
ALARM: JOBFAILURE       JOB: i3-chq-cspo-pd-batch-daily-renametable-file
STATUS: FAILURE         JOB: i3-imds-dcp-pd-bo1-35-filewatcher
STATUS: FAILURE         JOB: i3-imds-dcp-pd-bo1-05-ftpfilewatcher
STATUS: FAILURE         JOB: i3-imds-dcp-pd-bo1-35-filewatcher
STATUS: FAILURE         JOB: i3-imds-dcp-pd-bo1-05-ftpfilewatcher

Answer 1

如果您的正则表达式实现支持look-ahead assertions，请尝试以下操作：

^(STATUS|ALARM): +(JOB)?FAILURE +JOB: ((?!filewatch).)+$

确保^和$符合文件行开始/结束。

Answer 2

Gumbo是正确的。这里有一个参考，向您展示如何在将来做这些事情。 http://www.regular-expressions.info/completelines.html

正则表达式 - 忽略具有匹配文本的行

2 个答案: