HI Guys,
我有2个带日历扩展器的asp.net texbox。我想找出其中一个日期控件发生变化时两个日期之间的天数。如何使用jquery或javascript实现这一目标?
答案 0 :(得分:82)
这应该可以解决问题
var start = $('#start_date').val();
var end = $('#end_date').val();
// end - start returns difference in milliseconds
var diff = new Date(end - start);
// get days
var days = diff/1000/60/60/24;
实施例
var start = new Date("2010-04-01"),
end = new Date(),
diff = new Date(end - start),
days = diff/1000/60/60/24;
days; //=> 8.525845775462964
答案 1 :(得分:5)
1)Html
<input type="text" id="firstDate" name="firstDate"/>
<input type="text" id="secondDate" name="secondDate"/>
2)Jquery
$("#firstDate").datepicker({
});
$("#secondDate").datepicker({
onSelect: function () {
myfunc();
}
});
function myfunc(){
var start= $("#firstDate").datepicker("getDate");
var end= $("#secondDate").datepicker("getDate");
days = (end- start) / (1000 * 60 * 60 * 24);
alert(Math.round(days));
}
Jsfiddle工作示例here
答案 2 :(得分:1)
嗨, 这是我计算两个日期之间的差异的示例
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<script src="https://code.jquery.com/jquery.min.js"></script>
<title>JS Bin</title>
</head>
<body>
<br>
<input class='fromdate' type="date" />
<input class='todate' type="date" />
<div class='calculated' /><br>
<div class='minim' />
<input class='todate' type="submit" onclick='showDays()' />
</body>
</html>
这是计算差异的函数:
function showDays(){
var start = $('.fromdate').val();
var end = $('.todate').val();
var startDay = new Date(start);
var endDay = new Date(end);
var millisecondsPerDay = 1000 * 60 * 60 * 24;
var millisBetween = endDay.getTime() - startDay.getTime();
var days = millisBetween / millisecondsPerDay;
// Round down.
alert( Math.floor(days));
}
希望我能对您有所帮助
答案 3 :(得分:0)
两个日期之间的天数计算。
$(document).ready(function () {
$('.submit').on('click', function () {
var startDate = $('.start-date').val();
var endDate = $('.end-date').val();
var start = new Date(startDate);
var end = new Date(endDate);
var diffDate = (end - start) / (1000 * 60 * 60 * 24);
var days = Math.round(diffDate);
});
});
答案 4 :(得分:0)
这是我使用Math.floor()函数完成的方式:
var start = new Date($('#start').val());
var end = new Date($('#end').val());
var diff = Math.floor((end-start) / (365.25 * 24 * 60 * 60 * 1000));
console.log(diff);
您还可以使用Math.round()函数以这种方式进行操作:
var start = new Date($('#start').val());
var end = new Date($('#end').val());
var diff = new Date(end - start) / (1000 * 60 * 60 * 24 * 365.25);
var age = Math.round(diff);
console.log(age);
答案 5 :(得分:0)
**This is a simple way of getting the DAYS between two dates**
var d1 = moment($("#StartDate").data("DateTimePicker").date());
var d2 = moment($("#EndDate").data("DateTimePicker").date());
var diffInDays = d2.diff(d1, 'days');
if (diffInDays > 0)
{
$("#Total").val(diffInDays);
}
else
{
$("#Total").val(0);
}
答案 6 :(得分:0)
@Override
protected Map<String, String> getParams() throws AuthFailureError {
HashMap<String, String> map = new HashMap<>();
map.put("email", txtEmail.getText().toString().trim());
map.put("name", name_from_input);
map.put("password", txtPassword.getText().toString());
return map;
}
答案 7 :(得分:0)
dplyr
答案 8 :(得分:-2)
这是在两个日期之间获得DAYS的简单方法
var nites = dateDiff(arriveDate,departDate,"D");