SQL Server:选择行中的行

时间:2014-09-29 06:50:01

标签: sql sql-server

我在SQL Server中有以下表格

Names TypeID
-------------
JJ     23
KK     20 
LL     15
JJ     13
KK     18
JJ     10

我希望我的选择查询的结果显示如下

Names TypeID
---------------
JJ    23,13,10
KK    20,18
LL    15

我怎样才能做到这一点?请帮忙,我是sql的新手

5 个答案:

答案 0 :(得分:2)

之前已多次回答过这个问题。例如:Does T-SQL have an aggregate function to concatenate strings?

一个好的代码片段是这样的:

set nocount on;
declare @YourTable table (RowID int, HeaderValue int, ChildValue varchar(5))
insert into @YourTable VALUES (1,1,'CCC')
insert into @YourTable VALUES (2,2,'B<&>B')
insert into @YourTable VALUES (3,2,'AAA')
insert into @YourTable VALUES (4,3,'<br>')
insert into @YourTable VALUES (5,3,'A & Z')
set nocount off
SELECT
    t1.HeaderValue
        ,STUFF(
                   (SELECT
                        ', ' + t2.ChildValue
                        FROM @YourTable t2
                        WHERE t1.HeaderValue=t2.HeaderValue
                        ORDER BY t2.ChildValue
                        FOR XML PATH(''), TYPE
                   ).value('.','varchar(max)')
                   ,1,2, ''
              ) AS ChildValues
    FROM @YourTable t1
    GROUP BY t1.HeaderValue

此代码取自我发布链接的同一主题。

答案 1 :(得分:1)

drop table #t 
create table #t(names varchar(10),type1 int)
insert into #t values('JJ',23),
('KK',20),
('LL',15),
('JJ',13),
('KK',18),
('JJ',10)

select distinct names,stuff((select ',' +cast(type1 as varchar(10)) from #t t2 where t2.names=t1.names for xml path('') ),1,1,'') as TypeID
from #t t1

FIDDLE DEMO

答案 2 :(得分:0)

试试这个: -

SELECT Names, GROUP_CONCAT(TypeID)
FROM YOUR_TABLE
GROUP BY Names;

答案 3 :(得分:0)

试试这个

SELECT Names, TypeID = 
    STUFF((SELECT ', ' + Convert(nvarchar(2),TypeID)
           FROM your_table b 
           WHERE b.Names = a.Names 
          FOR XML PATH('')), 1, 2, '')
FROM your_table a
GROUP BY Names

答案 4 :(得分:-1)

试试这段代码

SELECT name, GROUP_CONCAT(typeid)
FROM test
GROUP BY name