使用java的递归方法绘制正方形

时间:2014-09-29 04:08:15

标签: java recursion applet paint

我正在尝试编写一个绘制主正方形的applet,然后使用递归方法在主正方形的角上绘制较小的正方形。我真的很困惑如何解决这个问题。我已经在其角落上绘制了其他正方形的正方形,但我需要递归地执行此过程,这就是我迷失的地方。我需要设置一个最小边长,以便递归方法知道何时停止。这是我的代码。

 import javax.swing.JApplet;

 import java.awt.*;
public class LabC extends JApplet
{
    public void paint(Graphics g)
    {
    g.drawRect(50, 100, 100, 100);
    g.drawRect(25, 75, 50, 50);
    g.drawRect(125, 75, 50, 50);
    g.drawRect(125, 175, 50, 50);
    g.drawRect(25, 175, 50, 50);


}
}

1 个答案:

答案 0 :(得分:1)

我认为这或多或少是你在寻找什么

    public static class LabC extends JLabel {

    public void paintRecursiveWraper(Graphics g, int minW, int minH, int x, int y, int w, int h) {
        g.drawRect(x, y, w, h);
        paintRecusive(g, minW, minH, x, y, w, h);
    }

    public void paintRecusive(Graphics g, int minW, int minH, int x, int y, int w, int h) {
        if (h <= minH || w <= minW) {
            return;
        }

        int newW, newH;
        int newX, newY;
        newW = (int) (w * scaleFactor);
        newH = (int) (h * scaleFactor);

        // Bot Left Square
        newX = x;
        newY = y;
        g.drawRect(newX, newY, newW, newH);
        paintRecusive(g, minW, minH, newX, newY, newW, newH);
        // Bot Right Square
        newX = (int) (x + w * (1 - scaleFactor));
        newY = y;
        g.drawRect(newX, newY, newW, newH);
        paintRecusive(g, minW, minH, newX, newY, newW, newH);
        // Top Left Square
        newX = x;
        newY = (int) (y + h * (1 - scaleFactor));
        g.drawRect(newX, newY, newW, newH);
        paintRecusive(g, minW, minH, newX, newY, newW, newH);
        // Top Right Square
        newX = (int) (x + w * (1 - scaleFactor));
        newY = (int) (y + h * (1 - scaleFactor));
        g.drawRect(newX, newY, newW, newH);
        paintRecusive(g, minW, minH, newX, newY, newW, newH);
    }

    public void paint(Graphics g) {
        paintRecursiveWraper(g, 10, 10, 0, 0, 1000, 1000);

    }
}

scaleFactor必须介于0和1之间

编辑*