Question

SELECT topics.*
FROM topics topics
    JOIN rh_topictags tt ON tt.topic_id = topics.topic_id
    JOIN rh_topictags_tag t ON tt.tag_id = t.id
    JOIN forums f ON f.forum_id = topics.forum_id
WHERE LOWER(t.tag) IN ('super', 'fun')
    AND f.rh_topictags_enabled = 1
    AND topics.forum_id IN (1, 2, 3, 4)
    AND topics.topic_visibility = 1
GROUP BY topics.topic_id
HAVING count(t.id) = 2
ORDER BY topics.topic_last_post_time DESC
LIMIT 0, 10

如何获取总体找到的行数（没有限制）？

我可以不使用SELECT FOUND_ROWS()，因为此查询必须在多个DBMS（mysql，mssql，oracle，postgres，sqlite，sqlite3）下运行。

不幸的是，这不起作用：

SELECT topics.*, COUNT(topics.*) AS result_count
FROM topics topics
    JOIN rh_topictags tt ON tt.topic_id = topics.topic_id
    JOIN rh_topictags_tag t ON tt.tag_id = t.id
    JOIN forums f ON f.forum_id = topics.forum_id
WHERE LOWER(t.tag) IN ('super', 'fun')
    AND f.rh_topictags_enabled = 1
    AND topics.forum_id IN (1, 2, 3, 4)
    AND topics.topic_visibility = 1
GROUP BY topics.topic_id
HAVING count(t.id) = 2
ORDER BY topics.topic_last_post_time DESC
LIMIT 0, 10

Answer 1

这个怎么样：

Select * 
from
( 
    SELECT topics.*, count(*) as result_count
    FROM topics topics
        JOIN rh_topictags tt ON tt.topic_id = topics.topic_id
        JOIN rh_topictags_tag t ON tt.tag_id = t.id
        JOIN forums f ON f.forum_id = topics.forum_id
    WHERE LOWER(t.tag) IN ('super', 'fun')
        AND f.rh_topictags_enabled = 1
        AND topics.forum_id IN (1, 2, 3, 4)
        AND topics.topic_visibility = 1
    GROUP BY topics.topic_id
    HAVING count(t.id) = 2
) a
ORDER BY a.topic_last_post_time DESC
LIMIT 0, 10

sql查询+限制+计数整体结果在一个查询？

1 个答案: