Question

我必须对防波堤进行建模，以控制某些海岸的权限。我的解决方案实现了一个类“Ship”和类“OilShip”，“FishingShip”和“CarriageShip”，我使用了继承并制作了

public class OilShip extends Ship{
 ...
} 
public class FishingShip extends Ship{
 ...
}
public class CarriageShip extends Ship{
 ...
}

在另一个班级，我有船舶船=新船（...）;而且我想以某种方式将油船变成船舶，即

public Class Abcd{
  Ship ship;

  public Abcd(OilShip oship){
  ship=oship; //*************
  }
}

代码似乎有问题，请告诉我。

Answer 1

请务必致电超级班级＆＃39;你的子类里面的构造函数＆＃39;构造

这个解决方案适用于我：

public class Ship {
    private String name;
    private int weight;

    public Ship(String name, int weight) {
        this.name = name;
        this.weight = weight;
    }
}

class OilShip extends Ship {
    private int oilCapacity;

    public OilShip(int oilCapacity, String name, int weight) {
        super(name, weight);
        this.oilCapacity = oilCapacity;
    }
}

class FishingShip extends Ship {
    private int fisherMen;

    public FishingShip(int fisherMen, String name, int weight) {
        super(name, weight);
        this.fisherMen = fisherMen;
    }
}

class CarriageShip extends Ship {
    private int containers;

    public CarriageShip(int containers, String name, int weight) {
        super(name, weight);
        this.containers = containers;
    }
}

如前所述，应始终为Java类指定名称，其中第一个字符为大写，每个新单词相同 - ＆gt;驼峰

你不需要不同的构造者。在这里使用继承背后的令人敬畏的事情是，无论超类中的哪个子类是什么？＃34; Ship＆＃34;你在＆＃34; abcd＆＃34;中加入你的构造函数，它将被接受：

public class Abcd { private Ship ship; public Abcd(Ship ship){ this.ship = ship; } }

如何将对象从类转换为超类

1 个答案: