您好我是python 2.7.3的新手,我试图在两个if语句之后编写自动退出子句。
import os
password = "Anhur"
attempt = 0
while (password != "Anhur") and (attempt <= 3):
password = raw_input("Password: ")
attempt = attempt + 1
if attempt == 3:
print ("You have used all your attempts, the system will now close..")
print (" The shifting sands have ended you.")
break
if (password == "Anhur"):
print ("You conquered the sands")
os.exit(1)
这就是我所拥有的,但它似乎无法工作我也尝试过sys.exit(0)。任何帮助都会很精彩。
答案 0 :(得分:1)
只需使用exit()
import os
password=""
attempt=0
while (password != "Anhur") and (attempt<3):
password=raw_input("Password: ")
attempt+=1
if (password == "Anhur"):
print ("You conquered the sands")
exit()
print ('''You have used all your attempts, the system will now close..")
The shifting sands have ended you.''')
答案 1 :(得分:0)
嗨rsm, 有用的答案。然而,初始代码是错误的,恕我直言无用。请尝试这个:
import os
password = ""
attempts = 0
found = False
while (attempts <= 2):
password = raw_input("Password: ")
attempts = attempts + 1
if (password == "Anhur") :
found = True
break
if found:
print ("You conquered the sands")
exit(0)
else:
print ("You have used all of your attempts, the system will now close..")
print (" The shifting sands have ended you.")
exit(1)
这允许在OS级别正确区分成功/失败,例如,在csh / tcsh中的变量状态(我工作时的默认shell)或更有用/现代shell中的其他方式。