Question

我在python中调用了一个带有许多可选参数的类。我以这种方式构造构造函数的原因是因为我想有两种可能性来创建一个雇员对象的实例。

def __init__(self, ssn=None, familyssn=None, first_name=None, last_name=None, middle_name=None, email=None, mobile_phone=None, phone=None, department=None, salary=None, employee_list=None):
  self.employee_list = employee_list or []

  dict_of_emp = {}
  list_of_emp = []
  self.ssn = ssn
  self.familyssn = familyssn
  self.first_name = first_name
  self.last_name = last_name
  self.middle_name = middle_name
  self.email = email
  self.mobile_phone = mobile_phone
  self.phone = phone
  self.department = department
  self.salary = salary

  list_of_emp.append(ssn)
  list_of_emp.append(familyssn)
  list_of_emp.append(first_name)
  list_of_emp.append(last_name)
  list_of_emp.append(middle_name)
  list_of_emp.append(email)
  list_of_emp.append(mobile_phone)
  list_of_emp.append(phone)
  list_of_emp.append(department)
  list_of_emp.append(salary)

  #print "listi i smid: ", list_of_emp
  Employee.empCount += 1

  print "loop through list in constructor: ", employee_list

这是调用构造函数的唯一方法吗？

emp = Employee(None, None, None, None, None, None, None, None, None, None, list_of_list_emp_to_register)

我发现它的语法相当丑陋！

Answer 1

没有。选项，如你所说的可选。因此Employee()相当于填写所有None s。这就是ssn=None等等。

要指定最后一个参数，只需说

emp = Employee(employee_list=list_of_list_emp_to_register)

Python构造函数，包含许多可选参数

1 个答案: