在R中绘制多变量时间序列的问题

时间:2014-09-27 15:33:49

标签: r plot time-series

我有一个10个物体的时间序列,沿12小时测量,以监测特定的变量。时间序列存储在如下数据框中:

> myTS
    hr1  hr2  hr3  hr4  hr5  hr6  hr7  hr8  hr9 hr10 hr11 hr12
1    43  108   71   64  112   46  115  375  187  163   55  190
2   153  123  110  141  107  139  105  137  126  277  316   48
3   159   65   65   69   70   73   65   66   65   66  139   90
4   310  300  256  251   25  208  219  180   63  134  454  351
5   183  225   20  313  245   30  267  345  279  330  36    88

我试图将这些绘制在单个绘图窗口上,其中x轴为时间,y轴为5个对象中的每一个,并使用不同的颜色区分5行。我已经尝试了plot.ts()函数,但它出错了:

Error in plotts(x = x, y = y, plot.type = plot.type, xy.labels = xy.labels,  : 
cannot plot more than 10 series as "multiple"

然后我尝试了lines()功能,但仍然无法正常工作。任何帮助请?? !!

2 个答案:

答案 0 :(得分:4)

以下可能有用:

ddf$id = rownames(ddf)
ddf
  hr1 hr2 hr3 hr4 hr5 hr6 hr7 hr8 hr9 hr10 hr11 hr12 id
1  43 108  71  64 112  46 115 375 187  163   55  190  1
2 153 123 110 141 107 139 105 137 126  277  316   48  2
3 159  65  65  69  70  73  65  66  65   66  139   90  3
4 310 300 256 251  25 208 219 180  63  134  454  351  4
5 183 225  20 313 245  30 267 345 279  330   36   88  5

library(reshape2)    
mm = melt(ddf, id='id')

library(ggplot2)
ggplot(mm)+geom_line(aes(x=variable, y=value, group=id, color=id))

enter image description here

答案 1 :(得分:3)

如果DF是数据框,这里有几种方法:

1)autoplot.zoo

library(zoo)
library(ggplot2)
autoplot(zoo(t(DF)), facets = NULL)

autoplot.zoo screenshot

2)ts.plot

ts.plot(t(DF), col = 1:5)
legend("topleft", legend = 1:5, col = 1:5, lty = 1)

ts.plot screenshot

3)matplot

matplot(t(DF), type = "o")

matplot screenshot

注意:我们将其用作DF(下次请使用dput输出您的数据。)

DF <-  structure(list(hr1 = c(43L, 153L, 159L, 310L, 183L), hr2 = c(108L, 
123L, 65L, 300L, 225L), hr3 = c(71L, 110L, 65L, 256L, 20L), hr4 = c(64L, 
141L, 69L, 251L, 313L), hr5 = c(112L, 107L, 70L, 25L, 245L), 
    hr6 = c(46L, 139L, 73L, 208L, 30L), hr7 = c(115L, 105L, 65L, 
    219L, 267L), hr8 = c(375L, 137L, 66L, 180L, 345L), hr9 = c(187L, 
    126L, 65L, 63L, 279L), hr10 = c(163L, 277L, 66L, 134L, 330L
    ), hr11 = c(55L, 316L, 139L, 454L, 36L), hr12 = c(190L, 48L, 
    90L, 351L, 88L)), .Names = c("hr1", "hr2", "hr3", "hr4", 
"hr5", "hr6", "hr7", "hr8", "hr9", "hr10", "hr11", "hr12"), 
class = "data.frame", row.names = c("1", "2", "3", "4", "5"))