我有一个基于PHP的网站用于工作。我在下表中回显了数据库中的所有作业。当我单击表格行中的作业时,它会在表格旁边的iframe中显示作业详细信息。
这是表格和iframe index.php
<table class="table1">
<tr>
<td colspan="3">
<?php
include "job.header.php";
?>
</td>
</tr>
<tr>
<td width="30%">
<div>
<?php
require "module/job.call.php";
?>
</div>
</td>
<td width="60%">
<iframe name="content" src="../module/job.unclicked.php">
</iframe>
</td>
<td width="20%"> </td>
</tr>
</table>
这是我从数据库中调用作业的代码job.call.php
<?php
$result = mysqli_query($conn,"SELECT * FROM job where approved='1' ORDER BY `CreatedTime` DESC");
echo "<table id='maintable' class='table-fill' border='0' cellpadding='0' cellspacing='0'>
<tr>
<th position='fixed' overflow='hidden' width='10%'>Job Title</th>
<th position='fixed' width='5%'>Company Name</th>
<th width='5%'>Closing Date</th>
</tr>";
while($row = mysqli_fetch_array($result) ) {
if (strlen($row['positiontitle']) > 20)
$row['positiontitle'] = substr($row['positiontitle'], 0, 60) . "...";
echo "<tr ref='job.details.php?id=".$row['id']."' target='content' class='positiontitle-link'>";
echo "<td><font style='text-shadow: none;'>" . $row['positiontitle'] . "</font></a></td>";
echo "<td>" . $row['companyname'] . "</td>";
echo "<td>" . $row['closingdate'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($conn);
?>
我希望当我点击表格行中的作业时,地址栏应该记录作业的ID。因为如果有人想分享这份工作,那么他们应该只为特定工作发送该地址。
现在显示如下
我希望它看起来像这样