我有这个数组
array(5) {
[0]=>
array(5) {
["id"]=>
int(1411667077)
["nachricht"]=>
string(13) "iiiiiiiiiiiii"
["user"]=>
string(15) "334607943355808"
["datum"]=>
string(16) "25.09.2014 19:44"
["deleted"]=>
string(0) ""
}
[1]=>
array(5) {
["id"]=>
int(1411701734)
["nachricht"]=>
string(2) "dd"
["user"]=>
string(15) "334607943355808"
["datum"]=>
string(16) "26.09.2014 05:22"
["deleted"]=>
string(0) ""
}
[2]=>
array(5) {
["id"]=>
int(1411701737)
["nachricht"]=>
string(6) "swfsfs"
["user"]=>
string(15) "334607943355808"
["datum"]=>
string(16) "26.09.2014 05:22"
["deleted"]=>
string(0) ""
}
[3]=>
array(5) {
["id"]=>
int(1411701739)
["nachricht"]=>
string(7) "egwegeg"
["user"]=>
string(15) "334607943355808"
["datum"]=>
string(16) "26.09.2014 05:22"
["deleted"]=>
string(0) ""
}
[4]=>
array(5) {
["id"]=>
int(1411742201)
["nachricht"]=>
string(3) "sss"
["user"]=>
string(15) "334607943355808"
["datum"]=>
string(16) "26.09.2014 16:36"
["deleted"]=>
string(0) ""
}
}
我想剪切id
1411701737
的位置,所以我尝试了:
foreach($array as $arr => $sub_arr)
{
if $sub_arr['id'] == 1411701737
{
break;
}
}
我知道我需要在foreach中创建一个全新的数组,但是不是可能有一个内置函数吗?
答案 0 :(得分:0)
$new = array();
foreach($array as $k) {
if($k['id'] == 1411701737) break;
array_push($new, $k);
}
var_dump($new);
Mooseman的答案可能是一种更快的方法,因为它不依赖于PHP函数调用将数组放入新数组中。但是,除非你在一组100k +以上的数组中这样做,否则它确实无关紧要。
答案 1 :(得分:0)
$arr_new = array(); //Define a new array
foreach($arr_old as $a) { //Loop through the old one
if($a['id'] === 1411701737) break; //If the value of id matches, leave the foreach loop
$arr_new[] = $a; //Else, copy this array to the new array
}
print_r($arr_new); //Print the new array