Question

我试图在两种不同的条件下获取相同变量的总和。只是想知道是否有办法将这些加在一起。查询的详细信息实际上并不太相关。基本上只是尝试取第一笔金额并加上第二笔金额。

例如 -

第一次查询：

  select sum(amt_tot)
  from agbgift, aprdclb
  where agbgift_id = '1' and agbgift_id = aprdclb_id

第二次查询：

  select sum(amt_tot)
  from agbgift, aprxref, aprdclb where 
  aprxref_id = '1' and
  agbgift_id = aprxref_xref_id and
  aprxref_id = aprdclb_id and 
  xref_code in ('SPS','BUS','ORG','OWN','FDN' );

我要找的最终结果是＆＃39; First Query Sum＆＃39; +＆＃39;第二个查询总和＆＃39;

Answer 1

在这种情况下，它就像这样简单：

SELECT
 /* Query 1 (in parentheses) */
 (select sum(amt_tot)
  from agbgift, aprdclb
  where agbgift_id = '1' and agbgift_id = aprdclb_id)

  + /* plus */

 /* Query 2 (also in parentheses) */
  (select sum(amt_tot)
  from agbgift, aprxref, aprdclb where 
  aprxref_id = '1' and
  agbgift_id = aprxref_xref_id and
  aprxref_id = aprdclb_id and 
  xref_code in ('SPS','BUS','ORG','OWN','FDN' ))

Answer 2

with子句使其变得简单，如果不起作用，则可以在from子句

中使用别名

with b (  select sum(amt_tot) as bsum
  from agbgift, aprxref, aprdclb where 
  aprxref_id = '1' and
  agbgift_id = aprxref_xref_id and
  aprxref_id = aprdclb_id and 
  xref_code in ('SPS','BUS','ORG','OWN','FDN' ))
, a (select sum(amt_tot) asum
  from agbgift, aprdclb
  where agbgift_id = '1' and agbgift_id = aprdclb_id   )   
select a.asum + b.bsum
from a, b

在这种情况下确实如此：

select a.asum + b.bsum
from (select sum(amt_tot) asum
  from agbgift, aprdclb
  where agbgift_id = '1' and agbgift_id = aprdclb_id) as a, 
  (  select sum(amt_tot) as bsum
  from agbgift, aprxref, aprdclb where 
  aprxref_id = '1' and
  agbgift_id = aprxref_xref_id and
  aprxref_id = aprdclb_id and 
  xref_code in ('SPS','BUS','ORG','OWN','FDN' )) as b

SQL，如何从两个不同的查询中求和两个和

2 个答案: