Question

我正在尝试使用“上一个”和“下一个”按钮按ID排序的时间返回一条记录。我遇到了一些代码问题。

<?php 
include ('header.php');
include ('connection.php');
//pagination starts here
if(isset($_GET['page'])){
$page = preg_replace('#[^0-9]#','',$_GET['page']);
}else{
$page = 1;
}
$perPage = 1;
$lastPage = cell($count / $perPage);

if($page < 1){
$page = 1;
}else if($page > $lastPage){
$page = $lastPage;
}

$limit = 'LIMIT ' .($page -1)*$perPage .',$perPage';

$query = mysql_query('SELECT LastName FROM residents ORDER BY ID DESC $limit');

if($lastPage != 1){

if($page != $lastPage){
    $next = $page + 1;
    $pagination.='<a href="AutoIncrement.php?page='.$next.">Next</a>';
}
//error occurs here
if($page != 1){
    $prev = $page - 1;
    $pagination.='<a href="AutoIncrement.php?page='.$prev.">Previous</a>';
}
}
?>

这一切似乎都没问题，除了我不断收到最后一个IF语句的错误。有什么想法吗？

Answer 1

我终于弄明白了问题所在。以下是我提出的建议：

<?php
//browsing feature of database
include ('connection.php');  
include ('header.php');
$count_query = mysql_query("SELECT NULL FROM residents");
$count = mysql_num_rows($count_query);

//pagination starts here
if(isset($_GET['page'])){
//$page = preg_replace("##[^0-9]","",$_GET['page']);
$page = $_GET['page'];
//echo "Page is ".$page;
}else{
$page = 1;
//echo "Page is one";
}
$perPage = 1;
$lastPage = ceil($count/$perPage);
if($page <1){
$page = 1;
}else if($page > $lastPage){
$page = $lastPage;
}

$limit = "LIMIT " .($page-1) * $perPage .", $perPage";

$query = mysql_query("SELECT * FROM residents ORDER BY ID ASC $limit");
if($lastPage != 1){


if($page != $lastPage){
    $next = $page + 1;
    $pagination.='<nav><ul class="pager"><li><a href=Browse.php?page='.$next.'>Next</a>          </li></ul><nav>';
}
 if($page != 1){
    $prev = $page - 1;
    $pagination.='<nav><ul class="pager"><li><a href=Browse.php?    page='.$prev.'>Previous</a></li></ul></nav>';
} 
}


while($row = mysql_fetch_array($query)){
$output.='<p><img src="upload/' . $row['Picture'].'" width="70" height="70"/></p>';
$output.= $row['FirstName']. '<br />';
$output.= $row['LastName']. '<br />';
$output.= $row['Address']. '<br />';
$output.= $row['Birthday']. '<br />';
$output.= $row['FormerResidence']. '<br />';
$output.= $row['Career']. '<br />';
$output.= $row['Education']. '<br />';
$output.= $row['SpecialInterests']. '<br />';


}
?>






<?php
    /*while($person = mysql_fetch_array($result)) {
        echo "<h3>" . $person['FirstName'] . "</h3>";
        echo "<p>" . $person['LastName'] . "</p>"; 
        echo "<p>" . $person['Address'] . "</p>";
        echo "<p>" . $person['Birthday'] . "</p>"; 
        echo "<p>" . $person['FormerResidence'] . "</p>";
        echo "<p>" . $person['Career'] . "</p>";
        echo "<p>" . $person['Education'] . "</p>";
        echo "<p>" . $person['SpecialInterests'] . "</p>";
        echo '<p><img src="upload/' . $person['Picture'].'" width="70" height="70"/>      </p>';
    }*/
?>
<h1>Browse Residents</h1>
<!-- Comment start
        <a href="nextandprevious.php?page='.$previous.">Previous</a>
        <a href="nextandprevious.php?page='.$next.">Next</a>
             Comment end -->

        <?php echo $output;?>
        <?php echo $pagination;?>

Answer 2

Limit和offset可用于获取特定记录，但这会产生过多的开销。而是在变量中获取整个表数据，将其传递给javascript并在javascript中迭代。

编辑1：我故意没有提供任何代码示例，因此您可以自己尝试一下。

Answer 3

然后您可以使用SELECT * FROM table ORDER BY LastName ASC Limit 1,1之类的查询。（对于下一个）然后在将限制改为2,1之后等等。

分页：使用PHP的上一页和下一页

3 个答案: