我正在尝试使用时尚的xmpp实现pub sub。下面是光滑的xmpp下的示例重构的发布和订阅代码。我正在做的是我通过user1 / resourceB从会话订阅user1 / resourceA的节点n1（节点的创建者）。问题是
当我从user1 / resourceB发布到节点n1时，我从同一会话中获取事件发布但不发布到其他会话。即从作为节点创建者的user1 / resourceA订阅节点n1。在这种情况下，我得到的是事件。
def create(self,node_name,config=None):
try :
self['xep_0060'].create_node(self.pubsubserver,node_name,config=config)
except:
logging.error('Could not create node: %s' % node_name)
def publish(self,node_name,payload,_id=None):
print 'entering pubsub publish'
payload_xml = ET.fromstring("<test xmlns='test'>%s</test>" % payload)
ET.dump(payload_xml)
try:
result = self['xep_0060'].publish(self.pubsubserver, node_name,payload=payload_xml)
except:
logging.error('Could not publish to: %s' % node_name)
def subscribe(self,node_name,cb,options=None):
try:
self['xep_0060'].map_node_event(node_name,node_name)
self.add_event_handler('n1_publish',cb)
result = self['xep_0060'].subscribe(jid=self.pubsubserver, node=node_name)
print('Subscribed to node %s' % (node_name))
except:
logging.error('Could not subscribe')
日志：
#logs for create node n1
xmlstream: 1728 SEND: <iq to="xmppserver.com" type="set" id="test@xmppserver.com/testff388888-4563-11e4-ad83-3c970eebb17011"><pubsub xmlns="http://jabber.org/protocol/pubsub">
<create node="n1" /></pubsub></iq>
xmlstream: 1603 RECV: <iq from="xmppserver.com" type="result" id="test@xmppserver.com/testff388888-4563-11e4-ad83-3c970eebb17011" to="test@xmppserver.com/testff388888-4563-11e4-ad83-3c970eebb170" />
#logs for subscribe to node n1 from session2
xmlstream: 1728 SEND: <iq to="xmppserver.com" type="set" id="test@xmppserver.com/test2d487986-4564-11e4-b710-3c970eebb1707"><pubsub xmlns="http://jabber.org/protocol/pubsub"><subscribe node="n1" jid="test@xmppserver.com" /></pubsub></iq>
xmlstream: 1603 RECV: <iq from="xmppserver.com" type="result" id="test@xmppserver.com/test2d487986-4564-11e4-b710-3c970eebb1707" to="test@xmppserver.com/test2d487986-4564-11e4-b710-3c970eebb170"><pubsub xmlns="http://jabber.org/protocol/pubsub"><subscription node="n1" jid="test@xmppserver.com" subscription="subscribed"><subscribe-options /></subscription></pubsub></iq>
#logs for publish to node1 from session1
publish n1 session1
test_pubsub: 59 publish to node n1 with data session1 :
entering pubsub publish
<ns0:test xmlns:ns0="test">session1</ns0:test>
<iq to="xmppserver.com" type="set" id="test@xmppserver.com/testff388888-4563-11e4-ad83-3c970eebb17013"><pubsub xmlns="http://jabber.org/protocol/pubsub"><publish node="n1"><item><test xmlns="test">session1</test></item></publish></pubsub></iq>
xmlstream: 1728 SEND: <iq to="xmppserver.com" type="set" id="test@xmppserver.com/testff388888-4563-11e4-ad83-3c970eebb17013"><pubsub xmlns="http://jabber.org/protocol/pubsub"><publish node="n1"><item><test xmlns="test">session1</test></item></publish></pubsub></iq>
xmlstream: 1603 RECV: <iq from="xmppserver.com" type="result" id="test@xmppserver.com/testff388888-4563-11e4-ad83-3c970eebb17013" to="test@xmppserver.com/testff388888-4563-11e4-ad83-3c970eebb170" />
xmlstream: 1603 RECV: <message to="test@xmppserver.com" from="test@xmppserver.com" id="n1__test@xmppserver.com__fE85u"><event xmlns="http://jabber.org/protocol/pubsub#event"><items node="n1"><item id="4be1b29a-4af8-4456-a5c8-0a311dabce4937"><test xmlns="test">session1</test></item></items></event></message>
xmlstream: 1156 Event triggered: pubsub_publish
test_pubsub: 36 1. create <node name>
xmlstream: 1603 RECV: <message to="test@xmppserver.com" from="test@xmppserver.com" id="n1__test@xmppserver.com__fE85u"><event xmlns="http://jabber.org/protocol/pubsub#event"><items node="n1"><item id="4be1b29a-4af8-4456-a5c8-0a311dabce4937"><test xmlns="test">session1</test></item></items></event></message>
我正在使用Openfire服务器进行Xmpp