Question

我知道这个问题比教堂里的阿门问过的次数多。但无论如何我会问。

我将参加丹麦的桌面游戏大会，我认为＆＃34;嘿，我们可以使用定位玩家短信服务＆＃34; 所以我建立它。但是，当我必须从一个数据库中取出一些数据，如phonenumber和名称。我需要将其插入另一个数据库（我的短信注入看起来）但一个变量只能存储1个数字，我需要存储10〜50个数字和名称这是我到目前为止所得到的。

    // escape variables for security
    $Name = mysqli_real_escape_string($con, $_POST['Name']);
    $Players = mysqli_real_escape_string($con, $_POST['Players']);
    $Game = mysqli_real_escape_string($con, $_POST['Game']);

    $besked = "Du har oprettet et spil med navn $Name og er et $Game som mangler $Players spiller(e).";
    echo $besked;
    echo "<br>";

    $result = mysqli_query($con,"SELECT * FROM brugere where $Game = 'Ja'");

    while($row = mysqli_fetch_array($result)) {
      echo $row['Navn'] . " " . $row['VCNummer'];
      echo "<br>";
    $PhoneNumber = $row['Phonenumber'];  

    }

    mysqli_close($con);

    ?>
    <html>
    <body>

    <form action="smssend.php" method="post">
    <input type="hidden" name="besked" value="<?php echo "$besked"; ?>"><br>
    <input type="hidden" name="PhoneNumber" value="<?php echo "$PhoneNumber"; ?>"><br>
    <input type="submit" value="Send data">
    </form>

    </body>
    </html>

当我试图把它放在其他数据库中时

    <?php
    $con=mysqli_connect("localhost","USER","PASSWORD","SMSDATABASE");
    // Check connection
    if (mysqli_connect_errno()) {
      echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }

    // escape variables for security

    $besked = mysqli_real_escape_string($con, $_POST["besked"]);
    $PhoneNumber = mysqli_real_escape_string($con, $_POST["PhoneNumber"]);


    $sql="INSERT INTO outbox (DestinationNumber, Class, TextDecoded)
    VALUES ('$PhoneNumber', '1', '$besked')";

    if (!mysqli_query($con,$sql)) {
      die('Error: ' . mysqli_error($con));
    }

    mysqli_close($con);

    ?>
    <meta http-equiv="refresh" content="0;url=../index.php">

我希望这是有道理的。

我试过以下

<?php
$con=mysqli_connect("localhost","USER","PASSWORD","DATABASE");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

// escape variables for security
$Name = mysqli_real_escape_string($con, $_POST['Name']);
$Players = mysqli_real_escape_string($con, $_POST['Players']);
$Game = mysqli_real_escape_string($con, $_POST['Game']);

$besked = "Du har oprettet et spil med navn $Name og er et $Game som mangler $Players spiller(e).";
echo $besked;
echo "<br>";

$result = mysqli_query($con,"SELECT * FROM brugere where $Game = 'Ja'");

$phone_numbers = array();
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
    $phone_numbers[] =  $row['Phonenumber'];  
}

mysqli_close($con);

?>
<html>
<body>

<form action="smssend.php" method="post">
<input type="hidden" name="besked" value="<?php echo "$besked"; ?>"><br>
<input type="hidden" name="PhoneNumber" value="<?php echo serialize($phone_numbers); ?>">
<input type="submit" value="Send data">
</form>

</body>
</html>

下一个PHP文件

<?php
$con=mysqli_connect("localhost","USER","PASSWORD","SMSDATABASE");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

// escape variables for security

$besked = mysqli_real_escape_string($con, $_POST["besked"]);
$Phone = unserialize($_POST["PhoneNumber"]);
var_dump($Phone);

/*$sql="INSERT INTO outbox (DestinationNumber, Class, TextDecoded)
VALUES ('$PhoneNumber', '1', '$besked')";

if (!mysqli_query($con,$sql)) {
  die('Error: ' . mysqli_error($con));
}
echo "Beskeden er sendt";

mysqli_close($con);
*/
?>

请注意我已在此部分取消了插入数据库。

但是当我尝试运行该文件时，我得到以下内容

布尔（假）

Answer 1

而不是

while($row = mysqli_fetch_array($result)) {
      echo $row['Navn'] . " " . $row['VCNummer'];
      echo "<br>";
      $PhoneNumber = $row['Phonenumber']; 
}

试试这个

$phone_numbers = array();
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
    $phone_numbers[] =  $row['Phonenumber'];  
}

然后尝试

var_dump($phone_numbers);

MySql导致数组

1 个答案: