让我们假设我们有以下实体:
@Entity
@DiscriminatorColumn(name="Type")
@Inheritance(strategy=InheritanceType.Joined)
public abstract class Employee extends Persistable<Long> {
private String firstName;
private String lastName;
//getters, setters
}
@Entity
@DiscriminatorValue("S")
public class SalariedEmployee extends Employee {
//various fields
}
@Entity
@DiscriminatorValue("C")
public class ContractEmployee extends Employee {
//various fields
}
@Entity
@DiscriminatorValue("H")
public class HourlyEmployee extends Employee {
//various fields
}
和Repository
public interface EmployeeRepository implements PagingAndSortingRepository<Employee, Long> {
}
我如何搜索查询可以说&#34;带给我所有不是HourlyEmployees&#34;的员工。显然我会要求对它们进行分页/排序,所以我可能不能findAll();
并且如果我没有弄错的话,只删除页面集合中的条目。
答案 0 :(得分:1)
请参阅JPQL类型运算符:
http://en.wikibooks.org/wiki/Java_Persistence/JPQL#JPQL_special_operators
JPA 2.0规范(第4.6.17.4节)给出了以下用法示例:
SELECT e
FROM Employee e
WHERE TYPE(e) IN (Exempt, Contractor)
SELECT e
FROM Employee e
WHERE TYPE(e) IN (:empType1, :empType2)
SELECT e
FROM Employee e
WHERE TYPE(e) IN :empTypes
SELECT TYPE(e)
FROM Employee e
WHERE TYPE(e) <> Exempt