Question

我在box2d中创建了一条带有RevoluteJoint和RopeJoint的绳子，但我遇到了一些问题：

有时，最后一段旋转，看起来它与绳索断开连接。
如何画这个东西？我创建一个每个链接大小的纹理。如果绳子没有移动，它看起来很好，但是一旦绳子移动并且不同的链节开始稍微旋转，你就会看到链节之间的间隙。

代码：

private void createChain(World world, Body anchorBody) {
  Body previousBody = anchorBody;

  FixtureDef fixtureDef = new FixtureDef();

  PolygonShape robeLinkShape = new PolygonShape();
  robeLinkShape.setAsBox(4 / PPM, 8 / PPM);
  fixtureDef.shape = robeLinkShape;
  fixtureDef.density = 0.1f;
  //    fixtureDef.friction = 1.0f;
  fixtureDef.restitution = 0.1f;
  fixtureDef.filter.maskBits = Box2DConst.BIT_PLAYER;
  fixtureDef.filter.categoryBits = Box2DConst.BIT_GROUND;

  float mapX = anchorBody.getPosition().x * PPM;
  float mapY = anchorBody.getPosition().y * PPM;

  BodyDef bodyDef = new BodyDef();
  bodyDef.angularDamping = 1.0f;
  bodyDef.linearDamping = 1.0f;

  //create rope
  for (int i = 0; i < 10; i++) {
    Float robeX = mapX / PPM;
    Float robeY = (mapY - (i * 16)) / PPM;
    bodyDef.type = BodyDef.BodyType.DynamicBody;
    bodyDef.position.set(robeX, robeY);

    final Body link = world.createBody(bodyDef);
    link.createFixture(fixtureDef);

    RevoluteJointDef jointDef = new RevoluteJointDef();
    jointDef.initialize(previousBody, link, new Vector2(robeX, robeY));

    //don't need the rope to collide itself
    jointDef.collideConnected = false;
    jointDef.enableLimit = false;

    // because we don't collide with other bodies in the rope, limit rotation to keep the rope bodies from rotating too much.
    jointDef.lowerAngle = -5.0f * MathUtils.degreesToRadians;
    jointDef.upperAngle = 5.0f * MathUtils.degreesToRadians;
    world.createJoint(jointDef);

    links.add(link);
    previousBody = link;
  }

  RopeJointDef ropeJointDef = new RopeJointDef();
  ropeJointDef.localAnchorB.set(0, 0);
  ropeJointDef.maxLength = 90.0f;
  ropeJointDef.bodyB = previousBody;
  ropeJointDef.bodyA = links.get(0);
  ropeJointDef.collideConnected = false;
  world.createJoint(ropeJointDef);
}

public void draw(final SpriteBatch batch) {
  Texture texture = FipiGame.res.get("rope");
  batch.begin();
  for (Body link : links) {
    float x = (link.getPosition().x * PPM) - 4;
    float y = (link.getPosition().y * PPM) - 8;

    float angleDeg = MathUtils.radiansToDegrees * link.getAngle();
    batch.draw(texture, x, y, 0, 0, texture.getWidth(), texture.getHeight(), 1f, 1f, angleDeg, 0,   0,
             texture.getWidth(), texture.getHeight(), false, false);
   }
batch.end();
}

Answer 1

而不是基于身体位置和旋转进行绘制：通过循环旋转关节位置（世界空间中的anchorA和anchorB的中点）创建一组点。然后绘制你的精灵，以便他们连接这些位置。这有点不准确，因为它不能完美地与刚体的位置对齐，但它应该看起来很好。

如何使用box2d构建和绘制一条漂亮的绳子

1 个答案: