Question

我试图使用几个for循环来遍历一个字符串数组来调用每个数组项。我在找到合适的代码来解决它时遇到了一些麻烦。我尝试过使用数组的全局定义等等。

var An = new Array(            
       "11111100011111",       
       "11111000011111",      
       "11110011001111", 
       "11100000000111", 
       "11001111110011", 
       "10011111111001");  
var Bn = new Array(            
       "1000000001",       
       "1001111001",      
       "1000000001", 
       "1000000001", 
       "1001111001", 
       "1000000001"); 

// This second part sits in a onload function.
var alphabet = "AB".split("");

for (x = 0; x < 6; x++) {       
    for (i = 0; i < 2; i++) {
     var my_object = {};
     my_object = window[alphabet[x] + 'n[' + i + ']'];
     my_object = window[my_object].replace(/0/g, "B");
     my_object = window[my_object].replace(/1/g, "_");
    }
}

Answer 1

您应该做的是将An和Bn放入对象中。这将使以后更容易引用。

var alphabet = {
    An: [
       "11111100011111",       
       "11111000011111",      
       "11110011001111", 
       "11100000000111", 
       "11001111110011", 
       "10011111111001"
    ],
    Bn: [
       "1000000001",       
       "1001111001",      
       "1000000001", 
       "1000000001", 
       "1001111001", 
       "1000000001"
    ]
};

然后你选择你想要的数组并循环它。

var arrays = ['A', 'B'];
for(var x = 0, xLen = arrays.length; x < xLen; x++){
    var my_key = arrays[x]+'n';
    for(var i = 0, iLen = alphabet[my_key].length; i < iLen; i++){
        alphabet[my_key][i] = alphabet[my_key][i].replace(/0/g, "B");
        alphabet[my_key][i] = alphabet[my_key][i].replace(/1/g, "_");
    }
}

实际上，对于内部for循环，您还可以使用Array.map。

var arrays = ['A', 'B'];
for(var x = 0, xLen = arrays.length; x < xLen; x++){
    var my_key = arrays[x]+'n';
    alphabet[my_key] = alphabet[my_key].map(function(val){
        val = val.replace(/0/g, "B");
        val = val.replace(/1/g, "_");
        return val;
    });
}

使用包含数组的数组变量修改数组中的字符串

1 个答案: