如何按关联数组值排序（复杂数组结构）？

时间：2014-09-25 08:09:44

标签： javascript arrays sorting

考虑以下内容：

我在HTML表中的数组中表示数据，例如：

image of table

1）我如何按b1或b3对数组进行排序？

我试过了：

＆＃13 ;
＆＃13; 
var o = {
    "orgs": {
        "655": {
            "data": {
                "cons": 30,
                "b3ports": 0,
                "b9": 2,
                "b1": 25,
                "b2": 14,
                "b3": 10,
                "ports": 0,
                "rica": 30
            },
            "depth": 1,
            "agents": [207072],
            "orgunit_id": "TEAM00655",
            "name": "TEAM00655: Jabba - Mooi River (Muhammad Jaffar)"
        },
        "853": {
            "data": {
                "cons": 356,
                "b3ports": 1,
                "b9": 8,
                "b1": 283,
                "b2": 122,
                "b3": 77,
                "ports": 1,
                "rica": 356
            },
            "depth": 2,
            "agents": [208162],
            "orgunit_id": "TEAM00853",
            "name": "TEAM00853: Jabba - Mooiriver (Bongiwe Gwala)"
        },
        "921": {
            "data": {
                "cons": 22,
                "b3ports": 0,
                "b9": 2,
                "b1": 20,
                "b2": 7,
                "b3": 5,
                "ports": 0,
                "rica": 22
            },
            "depth": 1,
            "agents": [210171, 212842],
            "orgunit_id": "TEAM00921",
            "name": "TEAM00921: Jabba  - Nolwazi Zungu"
        },
    },
    "agents": {
        "207072": {
            "name": "Bongiwe Gwala",
            "oid": 655,
            "depth": 1,
            "aid": "A0207072",
            "orgunit_id": "TEAM00655",
            "data": {
                "cons": 30,
                "b3ports": 0,
                "b9": 2,
                "b1": 25,
                "b2": 14,
                "b3": 10,
                "ports": 0,
                "rica": 30
            },
            "aname": "A0207072: Bongiwe Gwala",
            "oname": "TEAM00655: Jabba - Mooi River (Muhammad Jaffar)"
        },
        "208162": {
            "name": "Nkosikhona MADLALA",
            "oid": 853,
            "depth": 2,
            "aid": "A0208162",
            "orgunit_id": "TEAM00853",
            "data": {
                "cons": 356,
                "b3ports": 1,
                "b9": 8,
                "b1": 283,
                "b2": 122,
                "b3": 77,
                "ports": 1,
                "rica": 356
            },
            "aname": "A0208162: Nkosikhona MADLALA",
            "oname": "TEAM00853: Jabba - Mooiriver (Bongiwe Gwala)"
        },
        "212842": {
            "name": "SANELE KHUMALO",
            "oid": 921,
            "depth": 1,
            "aid": "A0212842",
            "orgunit_id": "TEAM00921",
            "data": {
                "cons": 22,
                "b3ports": 0,
                "b9": 2,
                "b1": 20,
                "b2": 7,
                "b3": 5,
                "ports": 0,
                "rica": 22
            },
            "aname": "A0212842: SANELE KHUMALO",
            "oname": "TEAM00921: Jabba  - Nolwazi Zungu"
        },
    },
"orglist": [853, 655, 921],
}

function sort_data(data, sortby, asc) {
  console.log(data);
  if (asc == "asc") {
    data.sort(function(a, b) {
      a.sortby - b.sortby;
    });
  } else {
    data.sort(function(a, b) {
      a.sortby + b.sortby;
    });
  }
  // update_data;
}

var a = sort_data(o, "b1", "asc");
console.log(a);
＆＃13; 
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
＆＃13;
＆＃13;
＆＃13; 这怎么会给我一个错误（要查看错误，请打开你的控制台）

更新

感谢@NicolasAlbert，我得到了分类工作。

现在我需要按agents订购。它需要首先按orgs排序，然后按agents排序我尝试过：

        if (asc == "desc") {
             data.orglist.sort(function(a, b) {
                a_org = data.orgs[a].data[sortby];
                b_org = data.orgs[b].data[sortby];
                a_agent = data.agents[a].data[sortby];
                b_agent = data.agents[b].data[sortby];
                // return d - c;
                return b_org - a_org &&  a_agent - b_agent;

                // data.agents[a].data[sortby] - data.agents[b].data[sortby]
            });
        } else {
            data.orglist.sort(function(a, b) {
                a_org = data.orgs[a].data[sortby];
                b_org = data.orgs[b].data[sortby];
                a_agent = data.agents[a].data[sortby];
                b_agent = data.agents[b].data[sortby];
                return a_org - b_org && a_agent - b_agent;
            });
        }

这无论如何都不起作用......

另一次更新

我修改了我的代码：

            data.orglist.sort(function(a, b) {
                a_org = data.orgs[a].data[sortby];
                b_org = data.orgs[b].data[sortby];
                agents = data.orgs[b].agents.sort(function(a, b){
                    a_agent = data.agents[a].data[sortby];
                    b_agent = data.agents[b].data[sortby];
                    return b_agent - a_agent
                });

                return b_org - a_org && agents;
            });

但是，这会同时对orgs和agents进行排序。

最新消息：

我让它工作，对orgs和agents进行排序，我必须创建两个排序函数：

    function sort_org(data, sortby, order) {
        /*
        Sort the orgs
        */
        var a_org, b_org;

        if (order == "desc") {
             data.orglist.sort(function(a, b) {
                a_org = data.orgs[a].data[sortby];
                b_org = data.orgs[b].data[sortby];                
                return b_org - a_org;
            });
        } else {
            data.orglist.sort(function(a, b) {
                a_org = data.orgs[a].data[sortby];
                b_org = data.orgs[b].data[sortby];
                return a_org - b_org;
            });
        }
    }

    function sort_agent(data, sortby, order) {
        /*
        Sort the agents
        */
        var a_agent, b_agent;

        if (order == "desc") {
            for (var orgid in data.orglist){
                data.orgs[data.orglist[orgid]].agents.sort(function(a, b){
                    a_agent = data.agents[a].data[sortby];
                    b_agent = data.agents[b].data[sortby];
                    return b_agent - a_agent
                })
            }
        } else {
            for (var orgid in data.orglist){
                data.orgs[data.orglist[orgid]].agents.sort(function(a, b){
                    a_agent = data.agents[a].data[sortby];
                    b_agent = data.agents[b].data[sortby];
                    return a_agent - b_agent
                })
            }
        }
    }

然后我只是连续调用函数......即

sort_org(o, "b1", "asc");
sort_agent(o, "b1", "asc");

我希望这可以帮助别人......

1 个答案:

答案 0 :(得分：1)

您只能在.sort个实例上使用Array方法，而不能Object。您的数据存储在键/值对象中，并且无法修改订单。

如果您想订购数据，则必须在其中引入Array（[]）。

您是否希望订购orglist数组：

var o = {
    "orgs": {
        "655": {
            "data": {
                "cons": 30,
                "b3ports": 0,
                "b9": 2,
                "b1": 25,
                "b2": 14,
                "b3": 10,
                "ports": 0,
                "rica": 30
            },
            "depth": 1,
            "agents": [207072],
            "orgunit_id": "TEAM00655",
            "name": "TEAM00655: Jabba - Mooi River (Muhammad Jaffar)"
        },
        "853": {
            "data": {
                "cons": 356,
                "b3ports": 1,
                "b9": 8,
                "b1": 283,
                "b2": 122,
                "b3": 77,
                "ports": 1,
                "rica": 356
            },
            "depth": 2,
            "agents": [208162],
            "orgunit_id": "TEAM00853",
            "name": "TEAM00853: Jabba - Mooiriver (Bongiwe Gwala)"
        },
        "921": {
            "data": {
                "cons": 22,
                "b3ports": 0,
                "b9": 2,
                "b1": 20,
                "b2": 7,
                "b3": 5,
                "ports": 0,
                "rica": 22
            },
            "depth": 1,
            "agents": [210171, 212842],
            "orgunit_id": "TEAM00921",
            "name": "TEAM00921: Jabba  - Nolwazi Zungu"
        },
    },
    "agents": {
        "207072": {
            "name": "Bongiwe Gwala",
            "oid": 655,
            "depth": 1,
            "aid": "A0207072",
            "orgunit_id": "TEAM00655",
            "data": {
                "cons": 30,
                "b3ports": 0,
                "b9": 2,
                "b1": 25,
                "b2": 14,
                "b3": 10,
                "ports": 0,
                "rica": 30
            },
            "aname": "A0207072: Bongiwe Gwala",
            "oname": "TEAM00655: Jabba - Mooi River (Muhammad Jaffar)"
        },
        "208162": {
            "name": "Nkosikhona MADLALA",
            "oid": 853,
            "depth": 2,
            "aid": "A0208162",
            "orgunit_id": "TEAM00853",
            "data": {
                "cons": 356,
                "b3ports": 1,
                "b9": 8,
                "b1": 283,
                "b2": 122,
                "b3": 77,
                "ports": 1,
                "rica": 356
            },
            "aname": "A0208162: Nkosikhona MADLALA",
            "oname": "TEAM00853: Jabba - Mooiriver (Bongiwe Gwala)"
        },
        "212842": {
            "name": "SANELE KHUMALO",
            "oid": 921,
            "depth": 1,
            "aid": "A0212842",
            "orgunit_id": "TEAM00921",
            "data": {
                "cons": 22,
                "b3ports": 0,
                "b9": 2,
                "b1": 20,
                "b2": 7,
                "b3": 5,
                "ports": 0,
                "rica": 22
            },
            "aname": "A0212842: SANELE KHUMALO",
            "oname": "TEAM00921: Jabba  - Nolwazi Zungu"
        },
    },
"orglist": [853, 655, 921]
}

function sort_data(data, sortby, asc) {
  console.log(data);
  
  if (asc == "asc") {
    data.orglist.sort(function(a, b) {
      data.orgs[a].data[sortby] - data.orgs[b].data[sortby];
    });
  } else {
    data.orglist.sort(function(a, b) {
      data.orgs[b].data[sortby] - data.orgs[a].data[sortby];
    });
  }
  // update_data;
}

sort_data(o, "b1", "asc");
console.log(o.orglist);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

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