有没有办法在Swift中获取设备型号名称（iPhone 4S，iPhone 5，iPhone 5S等）？
我知道有一个名为UIDevice.currentDevice().model的属性，但它只返回设备类型（iPod touch，iPhone，iPad，iPhone模拟器等）。
我也知道可以使用这种方法在Objective-C中轻松完成：
#import <sys/utsname.h>
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
但是我在Swift中开发我的iPhone应用程序，所以有人可以帮助我用同样的方法在Swift中解决这个问题吗？
答案 0 :(得分：803)
我在UIDevice上制作了这个“纯粹的Swift”扩展程序。
此版本适用于Swift 2或更高版本 如果您使用的是早期版本，请使用an older version of my answer。
如果您正在寻找更优雅的解决方案，您可以使用在GitHub上发布的my µ-framework DeviceKit（也可通过CocoaPods，Carthage和Swift Package Manager获得）。
以下是代码：
import UIKit
public extension UIDevice {
static let modelName: String = {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
func mapToDevice(identifier: String) -> String { // swiftlint:disable:this cyclomatic_complexity
#if os(iOS)
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad7,5", "iPad7,6": return "iPad 6"
case "iPad11,4", "iPad11,5": return "iPad Air (3rd generation)"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad11,1", "iPad11,2": return "iPad Mini 5"
case "iPad6,3", "iPad6,4": return "iPad Pro (9.7-inch)"
case "iPad6,7", "iPad6,8": return "iPad Pro (12.9-inch)"
case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)"
case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)"
case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4":return "iPad Pro (11-inch)"
case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8":return "iPad Pro (12.9-inch) (3rd generation)"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "iOS"))"
default: return identifier
}
#elseif os(tvOS)
switch identifier {
case "AppleTV5,3": return "Apple TV 4"
case "AppleTV6,2": return "Apple TV 4K"
case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "tvOS"))"
default: return identifier
}
#endif
}
return mapToDevice(identifier: identifier)
}()
}
你这样称呼它：
let modelName = UIDevice.modelName
对于真实设备，它返回例如“iPad Pro 9.7英寸”，对于模拟器，它返回“模拟器”+模拟器标识符，例如“模拟器iPad Pro 9.7英寸”
答案 1 :(得分：147)
此 Swift 3.0 示例将当前设备模型返回为enum常量（以避免与字符串文字直接比较）。枚举的原始值是String，包含人类可读的iOS设备名称。由于它是Swift，因此已识别设备的列表仅包含足以支持包含Swift的iOS版本的模型。以下用法示例使用了本答案末尾的实现：
switch UIDevice().type {
case .iPhone5:
print("No TouchID sensor")
case .iPhone5S:
fallthrough
case .iPhone6:
fallthrough
case .iPhone6plus:
fallthrough
case .iPad_Pro9_7:
fallthrough
case .iPad_Pro12_9:
fallthrough
case .iPhone7:
fallthrough
case .iPhone7plus:
print("Put your thumb on the " +
UIDevice().type.rawValue + " TouchID sensor")
case .unrecognized:
print("Device model unrecognized");
default:
print(UIDevice().type.rawValue + " not supported by this app");
}
对于新设备版本，以及Apple为同一设备系列添加新型号时，您的应用应该保持最新状态。例如， iPhone3,1 iPhone3,2 iPhone3,4 都是“iPhone 4”。避免编写不考虑新模型的代码，因此您的算法不会意外地无法配置或响应新设备。您可以参考此维护的 iOS Device Model #'s 列表，在战略时刻更新您的应用。
iOS包括与设备无关的接口，用于检测硬件功能和参数，例如屏幕尺寸。 Apple提供的通用接口通常是最安全，最受支持的机制，可以动态地将应用程序的行为调整到不同的硬件。然而，以下代码可用于原型设计，调试，测试或任何时间代码需要针对特定器件系列。此技术也可用于通过其公共/公认名称来描述当前设备。
Swift 3
// 1. Declare outside class definition (or in its own file).
// 2. UIKit must be included in file where this code is added.
// 3. Extends UIDevice class, thus is available anywhere in app.
//
// Usage example:
//
// if UIDevice().type == .simulator {
// print("You're running on the simulator... boring!")
// } else {
// print("Wow! Running on a \(UIDevice().type.rawValue)")
// }
import UIKit
public enum Model : String {
case simulator = "simulator/sandbox",
iPod1 = "iPod 1",
iPod2 = "iPod 2",
iPod3 = "iPod 3",
iPod4 = "iPod 4",
iPod5 = "iPod 5",
iPad2 = "iPad 2",
iPad3 = "iPad 3",
iPad4 = "iPad 4",
iPhone4 = "iPhone 4",
iPhone4S = "iPhone 4S",
iPhone5 = "iPhone 5",
iPhone5S = "iPhone 5S",
iPhone5C = "iPhone 5C",
iPadMini1 = "iPad Mini 1",
iPadMini2 = "iPad Mini 2",
iPadMini3 = "iPad Mini 3",
iPadAir1 = "iPad Air 1",
iPadAir2 = "iPad Air 2",
iPadPro9_7 = "iPad Pro 9.7\"",
iPadPro9_7_cell = "iPad Pro 9.7\" cellular",
iPadPro10_5 = "iPad Pro 10.5\"",
iPadPro10_5_cell = "iPad Pro 10.5\" cellular",
iPadPro12_9 = "iPad Pro 12.9\"",
iPadPro12_9_cell = "iPad Pro 12.9\" cellular",
iPhone6 = "iPhone 6",
iPhone6plus = "iPhone 6 Plus",
iPhone6S = "iPhone 6S",
iPhone6Splus = "iPhone 6S Plus",
iPhoneSE = "iPhone SE",
iPhone7 = "iPhone 7",
iPhone7plus = "iPhone 7 Plus",
iPhone8 = "iPhone 8",
iPhone8plus = "iPhone 8 Plus",
iPhoneX = "iPhone X",
iPhoneXS = "iPhone XS",
iPhoneXSmax = "iPhone XS Max",
iPhoneXR = "iPhone XR",
unrecognized = "?unrecognized?"
}
public extension UIDevice {
public var type: Model {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafePointer(to: &systemInfo.machine) {
$0.withMemoryRebound(to: CChar.self, capacity: 1) {
ptr in String.init(validatingUTF8: ptr)
}
}
var modelMap : [ String : Model ] = [
"i386" : .simulator,
"x86_64" : .simulator,
"iPod1,1" : .iPod1,
"iPod2,1" : .iPod2,
"iPod3,1" : .iPod3,
"iPod4,1" : .iPod4,
"iPod5,1" : .iPod5,
"iPad2,1" : .iPad2,
"iPad2,2" : .iPad2,
"iPad2,3" : .iPad2,
"iPad2,4" : .iPad2,
"iPad2,5" : .iPadMini1,
"iPad2,6" : .iPadMini1,
"iPad2,7" : .iPadMini1,
"iPhone3,1" : .iPhone4,
"iPhone3,2" : .iPhone4,
"iPhone3,3" : .iPhone4,
"iPhone4,1" : .iPhone4S,
"iPhone5,1" : .iPhone5,
"iPhone5,2" : .iPhone5,
"iPhone5,3" : .iPhone5C,
"iPhone5,4" : .iPhone5C,
"iPad3,1" : .iPad3,
"iPad3,2" : .iPad3,
"iPad3,3" : .iPad3,
"iPad3,4" : .iPad4,
"iPad3,5" : .iPad4,
"iPad3,6" : .iPad4,
"iPhone6,1" : .iPhone5S,
"iPhone6,2" : .iPhone5S,
"iPad4,1" : .iPadAir1,
"iPad4,2" : .iPadAir2,
"iPad4,4" : .iPadMini2,
"iPad4,5" : .iPadMini2,
"iPad4,6" : .iPadMini2,
"iPad4,7" : .iPadMini3,
"iPad4,8" : .iPadMini3,
"iPad4,9" : .iPadMini3,
"iPad6,3" : .iPadPro9_7,
"iPad6,11" : .iPadPro9_7,
"iPad6,4" : .iPadPro9_7_cell,
"iPad6,12" : .iPadPro9_7_cell,
"iPad6,7" : .iPadPro12_9,
"iPad6,8" : .iPadPro12_9_cell,
"iPad7,3" : .iPadPro10_5,
"iPad7,4" : .iPadPro10_5_cell,
"iPhone7,1" : .iPhone6plus,
"iPhone7,2" : .iPhone6,
"iPhone8,1" : .iPhone6S,
"iPhone8,2" : .iPhone6Splus,
"iPhone8,4" : .iPhoneSE,
"iPhone9,1" : .iPhone7,
"iPhone9,2" : .iPhone7plus,
"iPhone9,3" : .iPhone7,
"iPhone9,4" : .iPhone7plus,
"iPhone10,1" : .iPhone8,
"iPhone10,2" : .iPhone8plus,
"iPhone10,3" : .iPhoneX,
"iPhone10,6" : .iPhoneX,
"iPhone11,2" : .iPhoneXS,
"iPhone11,4" : .iPhoneXSmax,
"iPhone11,6" : .iPhoneXSmax,
"iPhone11,8" : .iPhoneXR
]
if let model = modelMap[String.init(validatingUTF8: modelCode!)!] {
return model
}
return Model.unrecognized
}
}
答案 2 :(得分：81)
另一个/简单的替代方案（在https://www.theiphonewiki.com/wiki/Models找到的模型标识符引用）：
更新了Swift 3/4/5的答案，包括字符串修剪和模拟器支持：
func modelIdentifier() -> String {
if let simulatorModelIdentifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] { return simulatorModelIdentifier }
var sysinfo = utsname()
uname(&sysinfo) // ignore return value
return String(bytes: Data(bytes: &sysinfo.machine, count: Int(_SYS_NAMELEN)), encoding: .ascii)!.trimmingCharacters(in: .controlCharacters)
}
Swift 2的原始答案：
func modelIdentifier() -> String {
var sysinfo = utsname()
uname(&sysinfo) // ignore return value
return NSString(bytes: &sysinfo.machine, length: Int(_SYS_NAMELEN), encoding: NSASCIIStringEncoding)! as String
}
答案 3 :(得分：72)
以及最新的 iPad Pro 11＆＃34; ， iPad Air第三代和 iPad Pro 3代
即使它是模拟器，此方法也会检测到正确的模型。 （在模拟器中运行的模拟器设备模型的确切名称）
public enum Model : String {
//Simulator
case simulator = "simulator/sandbox",
//iPod
iPod1 = "iPod 1",
iPod2 = "iPod 2",
iPod3 = "iPod 3",
iPod4 = "iPod 4",
iPod5 = "iPod 5",
//iPad
iPad2 = "iPad 2",
iPad3 = "iPad 3",
iPad4 = "iPad 4",
iPadAir = "iPad Air ",
iPadAir2 = "iPad Air 2",
iPadAir3 = "iPad Air 3",
iPad5 = "iPad 5", //iPad 2017
iPad6 = "iPad 6", //iPad 2018
//iPad Mini
iPadMini = "iPad Mini",
iPadMini2 = "iPad Mini 2",
iPadMini3 = "iPad Mini 3",
iPadMini4 = "iPad Mini 4",
iPadMini5 = "iPad Mini 5",
//iPad Pro
iPadPro9_7 = "iPad Pro 9.7\"",
iPadPro10_5 = "iPad Pro 10.5\"",
iPadPro11 = "iPad Pro 11\"",
iPadPro12_9 = "iPad Pro 12.9\"",
iPadPro2_12_9 = "iPad Pro 2 12.9\"",
iPadPro3_12_9 = "iPad Pro 3 12.9\"",
//iPhone
iPhone4 = "iPhone 4",
iPhone4S = "iPhone 4S",
iPhone5 = "iPhone 5",
iPhone5S = "iPhone 5S",
iPhone5C = "iPhone 5C",
iPhone6 = "iPhone 6",
iPhone6Plus = "iPhone 6 Plus",
iPhone6S = "iPhone 6S",
iPhone6SPlus = "iPhone 6S Plus",
iPhoneSE = "iPhone SE",
iPhone7 = "iPhone 7",
iPhone7Plus = "iPhone 7 Plus",
iPhone8 = "iPhone 8",
iPhone8Plus = "iPhone 8 Plus",
iPhoneX = "iPhone X",
iPhoneXS = "iPhone XS",
iPhoneXSMax = "iPhone XS Max",
iPhoneXR = "iPhone XR",
//Apple TV
AppleTV = "Apple TV",
AppleTV_4K = "Apple TV 4K",
unrecognized = "?unrecognized?"
}
// #-#-#-#-#-#-#-#-#-#-#-#-#
// MARK: UIDevice extensions
// #-#-#-#-#-#-#-#-#-#-#-#-#
public extension UIDevice {
var type: Model {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafePointer(to: &systemInfo.machine) {
$0.withMemoryRebound(to: CChar.self, capacity: 1) {
ptr in String.init(validatingUTF8: ptr)
}
}
var modelMap : [String: Model] = [
//Simulator
"i386" : .simulator,
"x86_64" : .simulator,
//iPod
"iPod1,1" : .iPod1,
"iPod2,1" : .iPod2,
"iPod3,1" : .iPod3,
"iPod4,1" : .iPod4,
"iPod5,1" : .iPod5,
//iPad
"iPad2,1" : .iPad2,
"iPad2,2" : .iPad2,
"iPad2,3" : .iPad2,
"iPad2,4" : .iPad2,
"iPad3,1" : .iPad3,
"iPad3,2" : .iPad3,
"iPad3,3" : .iPad3,
"iPad3,4" : .iPad4,
"iPad3,5" : .iPad4,
"iPad3,6" : .iPad4,
"iPad4,1" : .iPadAir,
"iPad4,2" : .iPadAir,
"iPad4,3" : .iPadAir,
"iPad5,3" : .iPadAir2,
"iPad5,4" : .iPadAir2,
"iPad6,11" : .iPad5, //iPad 2017
"iPad6,12" : .iPad5,
"iPad7,5" : .iPad6, //iPad 2018
"iPad7,6" : .iPad6,
//iPad Mini
"iPad2,5" : .iPadMini,
"iPad2,6" : .iPadMini,
"iPad2,7" : .iPadMini,
"iPad4,4" : .iPadMini2,
"iPad4,5" : .iPadMini2,
"iPad4,6" : .iPadMini2,
"iPad4,7" : .iPadMini3,
"iPad4,8" : .iPadMini3,
"iPad4,9" : .iPadMini3,
"iPad5,1" : .iPadMini4,
"iPad5,2" : .iPadMini4,
"iPad11,1" : .iPadMini5,
"iPad11,2" : .iPadMini5,
//iPad Pro
"iPad6,3" : .iPadPro9_7,
"iPad6,4" : .iPadPro9_7,
"iPad7,3" : .iPadPro10_5,
"iPad7,4" : .iPadPro10_5,
"iPad6,7" : .iPadPro12_9,
"iPad6,8" : .iPadPro12_9,
"iPad7,1" : .iPadPro2_12_9,
"iPad7,2" : .iPadPro2_12_9,
"iPad8,1" : .iPadPro11,
"iPad8,2" : .iPadPro11,
"iPad8,3" : .iPadPro11,
"iPad8,4" : .iPadPro11,
"iPad8,5" : .iPadPro3_12_9,
"iPad8,6" : .iPadPro3_12_9,
"iPad8,7" : .iPadPro3_12_9,
"iPad8,8" : .iPadPro3_12_9,
//iPad Air
"iPad11,3" : .iPadAir3,
"iPad11,4" : .iPadAir3,
//iPhone
"iPhone3,1" : .iPhone4,
"iPhone3,2" : .iPhone4,
"iPhone3,3" : .iPhone4,
"iPhone4,1" : .iPhone4S,
"iPhone5,1" : .iPhone5,
"iPhone5,2" : .iPhone5,
"iPhone5,3" : .iPhone5C,
"iPhone5,4" : .iPhone5C,
"iPhone6,1" : .iPhone5S,
"iPhone6,2" : .iPhone5S,
"iPhone7,1" : .iPhone6Plus,
"iPhone7,2" : .iPhone6,
"iPhone8,1" : .iPhone6S,
"iPhone8,2" : .iPhone6SPlus,
"iPhone8,4" : .iPhoneSE,
"iPhone9,1" : .iPhone7,
"iPhone9,3" : .iPhone7,
"iPhone9,2" : .iPhone7Plus,
"iPhone9,4" : .iPhone7Plus,
"iPhone10,1" : .iPhone8,
"iPhone10,4" : .iPhone8,
"iPhone10,2" : .iPhone8Plus,
"iPhone10,5" : .iPhone8Plus,
"iPhone10,3" : .iPhoneX,
"iPhone10,6" : .iPhoneX,
"iPhone11,2" : .iPhoneXS,
"iPhone11,4" : .iPhoneXSMax,
"iPhone11,6" : .iPhoneXSMax,
"iPhone11,8" : .iPhoneXR,
//Apple TV
"AppleTV5,3" : .AppleTV,
"AppleTV6,2" : .AppleTV_4K
]
if let model = modelMap[String.init(validatingUTF8: modelCode!)!] {
if model == .simulator {
if let simModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
if let simModel = modelMap[String.init(validatingUTF8: simModelCode)!] {
return simModel
}
}
}
return model
}
return Model.unrecognized
}
}
<强>用法： 您可以使用以下命令获取设备模型：
let deviceType = UIDevice().type
或打印完整的字符串：
print("Running on: \(UIDevice().type)")
Output -> "iPhone X"
案例的另一个例子：
var myDefaultFontSize: CGFloat = 26.0
switch UIDevice().type {
case .iPhoneSE, .iPhone5, .iPhone5S: print("default value")
case .iPhone6, .iPhone7, .iPhone8, .iPhone6S, .iPhoneX: myDefaultFontSize += 4
default: break
}
对于Apple设备型号，请访问：https://www.theiphonewiki.com/wiki/Models
答案 4 :(得分：17)
对于设备和模拟器， 创建一个名为UIDevice.swift的新swift文件
添加以下代码
import UIKit
public extension UIDevice {
var modelName: String {
#if (arch(i386) || arch(x86_64)) && os(iOS)
let DEVICE_IS_SIMULATOR = true
#else
let DEVICE_IS_SIMULATOR = false
#endif
var machineString : String = ""
if DEVICE_IS_SIMULATOR == true
{
if let dir = NSProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
machineString = dir
}
}
else {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
machineString = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 where value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
}
switch machineString {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,7", "iPad6,8": return "iPad Pro"
case "AppleTV5,3": return "Apple TV"
default: return machineString
}
}
}
然后在你的viewcontroller中，
let deviceType = UIDevice.currentDevice().modelName
if deviceType.lowercaseString.rangeOfString("iphone 4") != nil {
print("iPhone 4 or iphone 4s")
}
else if deviceType.lowercaseString.rangeOfString("iphone 5") != nil {
print("iPhone 5 or iphone 5s or iphone 5c")
}
else if deviceType.lowercaseString.rangeOfString("iphone 6") != nil {
print("iPhone 6 Series")
}
答案 5 :(得分：16)
我在UIDevice上创建了另一个示例扩展，以包含基于@HAS answer的模拟器模型标识符：
public extension UIDevice {
/// pares the deveice name as the standard name
var modelName: String {
#if (arch(i386) || arch(x86_64)) && os(iOS)
let identifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"]!
#else
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 , value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
#endif
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad7,5", "iPad7,6": return "iPad 6"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)"
case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)"
case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4":return "iPad Pro (11-inch)"
case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8":return "iPad Pro (12.9-inch) (3rd generation)"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
default: return identifier
}
}
}
Swift 4.x版本：
public extension UIDevice {
/// pares the deveice name as the standard name
var modelName: String {
#if targetEnvironment(simulator)
let identifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"]!
#else
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 , value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
#endif
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad7,5", "iPad7,6": return "iPad 6"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)"
case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)"
case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4":return "iPad Pro (11-inch)"
case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8":return "iPad Pro (12.9-inch) (3rd generation)"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
default: return identifier
}
}
}
上面的Swift3.2工作正常：
let modelName = UIDevice.current.modelName
答案 6 :(得分：11)
处理c结构很快就会很痛苦。特别是如果它们中有某种c阵列。这是我的解决方案：继续使用objective-c。只需创建一个包装器objective-c类来完成这项工作，然后在swift中使用该类。这是一个完整的示例类：
@interface DeviceInfo : NSObject
+ (NSString *)model;
@end
#import "DeviceInfo.h"
#import <sys/utsname.h>
@implementation DeviceInfo
+ (NSString *)model
{
struct utsname systemInfo;
uname(&systemInfo);
return [NSString stringWithCString: systemInfo.machine encoding: NSUTF8StringEncoding];
}
@end
在迅速的一面：
let deviceModel = DeviceInfo.model()
答案 7 :(得分：8)
我根据一些给定的答案实现了一个超轻量级库来检测使用过的设备：https://github.com/schickling/Device.swift
可以通过Carthage进行安装，并按照以下方式使用：
import Device
let deviceType = UIDevice.currentDevice().deviceType
switch deviceType {
case .IPhone6: print("Do stuff for iPhone6")
case .IPadMini: print("Do stuff for iPad mini")
default: print("Check other available cases of DeviceType")
}
答案 8 :(得分：8)
我发现很多所有这些答案都使用字符串。我决定改变@HAS的答案来使用枚举：
public enum Devices: String {
case IPodTouch5
case IPodTouch6
case IPhone4
case IPhone4S
case IPhone5
case IPhone5C
case IPhone5S
case IPhone6
case IPhone6Plus
case IPhone6S
case IPhone6SPlus
case IPhone7
case IPhone7Plus
case IPhoneSE
case IPad2
case IPad3
case IPad4
case IPadAir
case IPadAir2
case IPadMini
case IPadMini2
case IPadMini3
case IPadMini4
case IPadPro
case AppleTV
case Simulator
case Other
}
public extension UIDevice {
public var modelName: Devices {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 , value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPod5,1": return Devices.IPodTouch5
case "iPod7,1": return Devices.IPodTouch6
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return Devices.IPhone4
case "iPhone4,1": return Devices.IPhone4S
case "iPhone5,1", "iPhone5,2": return Devices.IPhone5
case "iPhone5,3", "iPhone5,4": return Devices.IPhone5C
case "iPhone6,1", "iPhone6,2": return Devices.IPhone5S
case "iPhone7,2": return Devices.IPhone6
case "iPhone7,1": return Devices.IPhone6Plus
case "iPhone8,1": return Devices.IPhone6S
case "iPhone8,2": return Devices.IPhone6SPlus
case "iPhone9,1", "iPhone9,3": return Devices.IPhone7
case "iPhone9,2", "iPhone9,4": return Devices.IPhone7Plus
case "iPhone8,4": return Devices.IPhoneSE
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return Devices.IPad2
case "iPad3,1", "iPad3,2", "iPad3,3": return Devices.IPad3
case "iPad3,4", "iPad3,5", "iPad3,6": return Devices.IPad4
case "iPad4,1", "iPad4,2", "iPad4,3": return Devices.IPadAir
case "iPad5,3", "iPad5,4": return Devices.IPadAir2
case "iPad2,5", "iPad2,6", "iPad2,7": return Devices.IPadMini
case "iPad4,4", "iPad4,5", "iPad4,6": return Devices.IPadMini2
case "iPad4,7", "iPad4,8", "iPad4,9": return Devices.IPadMini3
case "iPad5,1", "iPad5,2": return Devices.IPadMini4
case "iPad6,3", "iPad6,4", "iPad6,7", "iPad6,8":return Devices.IPadPro
case "AppleTV5,3": return Devices.AppleTV
case "i386", "x86_64": return Devices.Simulator
default: return Devices.Other
}
}
}
答案 9 :(得分：6)
当您使用Swift 3时，接受的答案存在一些问题！ 这个答案（灵感来自NAZIK）适用于Swift 3和新的iPhone型号：
import UIKit
public extension UIDevice {
var modelName: String {
#if (arch(i386) || arch(x86_64)) && os(iOS)
let DEVICE_IS_SIMULATOR = true
#else
let DEVICE_IS_SIMULATOR = false
#endif
var machineString = String()
if DEVICE_IS_SIMULATOR == true
{
if let dir = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
machineString = dir
}
}
else {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
machineString = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8 , value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
}
switch machineString {
case "iPod4,1": return "iPod Touch 4G"
case "iPod5,1": return "iPod Touch 5G"
case "iPod7,1": return "iPod Touch 6G"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone8,4": return "iPhone SE"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone 9,4": return "iPhone 7 Plus"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro (9.7 inch)"
case "iPad6,7", "iPad6,8": return "iPad Pro (12.9 inch)"
case "AppleTV5,3": return "Apple TV"
default: return machineString
}
}
}
答案 10 :(得分：5)
使用Swift 3（Xcode 8.3）
func deviceName() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let str = withUnsafePointer(to: &systemInfo.machine.0) { ptr in
return String(cString: ptr)
}
return str
}
注意：根据官方开发论坛的答案，以这种方式使用元组是安全的。大Int8元组的内存对齐方式与它是一个大的Int8数组相同。即：连续而非填充。
答案 11 :(得分：5)
var platform: String? {
var systemInfo = utsname()
uname(&systemInfo)
return withUnsafeMutablePointer(&systemInfo.machine) { ptr in String.fromCString(UnsafePointer<CChar>(ptr)) }
}
答案 12 :(得分：4)
Swift 3.0或更高版本
import UIKit
class ViewController: UIViewController {
let device = UIDevice.current
override func viewDidLoad() {
super.viewDidLoad()
let model = device.model
print(model) // e.g. "iPhone"
let modelName = device.modelName
print(modelName) // e.g. "iPhone 6" /* see the extension */
let deviceName = device.name
print(deviceName) // e.g. "My iPhone"
let systemName = device.systemName
print(systemName) // e.g. "iOS"
let systemVersion = device.systemVersion
print(systemVersion) // e.g. "10.3.2"
if let identifierForVendor = device.identifierForVendor {
print(identifierForVendor) // e.g. "E1X2XX34-5X6X-7890-123X-XXX456C78901"
}
}
}
并添加以下扩展程序
extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPod5,1": return "iPod Touch 5"
case "iPod7,1": return "iPod Touch 6"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone8,4": return "iPhone SE"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4":return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad 3"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad 4"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad6,11", "iPad6,12": return "iPad 5"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad Mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad Mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad Mini 3"
case "iPad5,1", "iPad5,2": return "iPad Mini 4"
case "iPad6,3", "iPad6,4": return "iPad Pro 9.7 Inch"
case "iPad6,7", "iPad6,8": return "iPad Pro 12.9 Inch"
case "iPad7,1", "iPad7,2": return "iPad Pro 12.9 Inch 2. Generation"
case "iPad7,3", "iPad7,4": return "iPad Pro 10.5 Inch"
case "AppleTV5,3": return "Apple TV"
case "i386", "x86_64": return "Simulator"
default: return identifier
}
}
}
答案 13 :(得分：3)
在Swift 3中它会是
UIDevice.current.model
答案 14 :(得分：3)
您可以使用BDLocalizedDevicesModels框架来解析设备信息并获取名称。
然后只需在您的代码中调用UIDevice.currentDevice.productName。
答案 15 :(得分：3)
这里是一个没有强力解包的修改和Swift 3.0：
import Foundation
import UIKit
public enum Model : String {
case simulator = "simulator/sandbox",
iPod1 = "iPod 1",
iPod2 = "iPod 2",
iPod3 = "iPod 3",
iPod4 = "iPod 4",
iPod5 = "iPod 5",
iPad2 = "iPad 2",
iPad3 = "iPad 3",
iPad4 = "iPad 4",
iPhone4 = "iPhone 4",
iPhone4S = "iPhone 4S",
iPhone5 = "iPhone 5",
iPhone5S = "iPhone 5S",
iPhone5C = "iPhone 5C",
iPadMini1 = "iPad Mini 1",
iPadMini2 = "iPad Mini 2",
iPadMini3 = "iPad Mini 3",
iPadAir1 = "iPad Air 1",
iPadAir2 = "iPad Air 2",
iPhone6 = "iPhone 6",
iPhone6plus = "iPhone 6 Plus",
iPhone6S = "iPhone 6S",
iPhone6Splus = "iPhone 6S Plus",
iPhoneSE = "iPhone SE",
iPhone7 = "iPhone 7",
iPhone7plus = "iPhone 7 Plus",
unrecognized = "?unrecognized?"
}
public extension UIDevice {
public var type: Model {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafePointer(to: &systemInfo.machine) {
$0.withMemoryRebound(to: CChar.self, capacity: 1) {
ptr in String.init(validatingUTF8: ptr)
}
}
var modelMap : [ String : Model ] = [
"i386" : .simulator,
"x86_64" : .simulator,
"iPod1,1" : .iPod1,
"iPod2,1" : .iPod2,
"iPod3,1" : .iPod3,
"iPod4,1" : .iPod4,
"iPod5,1" : .iPod5,
"iPad2,1" : .iPad2,
"iPad2,2" : .iPad2,
"iPad2,3" : .iPad2,
"iPad2,4" : .iPad2,
"iPad2,5" : .iPadMini1,
"iPad2,6" : .iPadMini1,
"iPad2,7" : .iPadMini1,
"iPhone3,1" : .iPhone4,
"iPhone3,2" : .iPhone4,
"iPhone3,3" : .iPhone4,
"iPhone4,1" : .iPhone4S,
"iPhone5,1" : .iPhone5,
"iPhone5,2" : .iPhone5,
"iPhone5,3" : .iPhone5C,
"iPhone5,4" : .iPhone5C,
"iPad3,1" : .iPad3,
"iPad3,2" : .iPad3,
"iPad3,3" : .iPad3,
"iPad3,4" : .iPad4,
"iPad3,5" : .iPad4,
"iPad3,6" : .iPad4,
"iPhone6,1" : .iPhone5S,
"iPhone6,2" : .iPhone5S,
"iPad4,1" : .iPadAir1,
"iPad4,2" : .iPadAir2,
"iPad4,4" : .iPadMini2,
"iPad4,5" : .iPadMini2,
"iPad4,6" : .iPadMini2,
"iPad4,7" : .iPadMini3,
"iPad4,8" : .iPadMini3,
"iPad4,9" : .iPadMini3,
"iPhone7,1" : .iPhone6plus,
"iPhone7,2" : .iPhone6,
"iPhone8,1" : .iPhone6S,
"iPhone8,2" : .iPhone6Splus,
"iPhone8,4" : .iPhoneSE,
"iPhone9,1" : .iPhone7,
"iPhone9,2" : .iPhone7plus,
"iPhone9,3" : .iPhone7,
"iPhone9,4" : .iPhone7plus,
]
guard let safeModelCode = modelCode else {
return Model.unrecognized
}
guard let modelString = String.init(validatingUTF8: safeModelCode) else {
return Model.unrecognized
}
guard let model = modelMap[modelString] else {
return Model.unrecognized
}
return model
}
}
答案 16 :(得分：2)
以下是获取硬件字符串的代码，但您需要比较这些硬件字符串以了解它是哪个设备。我创建了一个包含几乎所有设备字符串的类（我们使用新设备保持字符串最新）。它易于使用，请检查
Swift ：GitHub/DeviceGuru
Objective-C ：GitHub/DeviceUtil
public func hardwareString() -> String {
var name: [Int32] = [CTL_HW, HW_MACHINE]
var size: Int = 2
sysctl(&name, 2, nil, &size, &name, 0)
var hw_machine = [CChar](count: Int(size), repeatedValue: 0)
sysctl(&name, 2, &hw_machine, &size, &name, 0)
let hardware: String = String.fromCString(hw_machine)!
return hardware
}
答案 17 :(得分：2)
SWIFT 3.1
只需拨打utsname：即可获得两分钱 func platform() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let size = Int(_SYS_NAMELEN) // is 32, but posix AND its init is 256....
let s = withUnsafeMutablePointer(to: &systemInfo.machine) {p in
p.withMemoryRebound(to: CChar.self, capacity: size, {p2 in
return String(cString: p2)
})
}
return s
}
和其他人一样，但对于C / Swift的所有复杂性以及后面的内容都有点清晰。 ）：
返回诸如“x86_64”
之类的值答案 18 :(得分：2)
基于此answer和此answer。我创建了一个公开的gist
如何使用
let boolean: Bool = UIDevice.isDevice(ofType: .iPhoneX)
// true or false
let specificDevice: DeviceModel.Model = UIDevice.modelType
// iPhone6s, iPhoneX, iPad etc...
let model: DeviceModel = UIDevice.model
// .simulator(let specificDevice), .real(let specificDevice),
// .unrecognizedSimulator(let string), .unrecognized(let string)
let modelName: String = UIDevice.model.name
// iPhone 6, iPhone X, etc...
这是要点内的代码
public extension UIDevice {
public static var modelCode: String {
if let simulatorModelIdentifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] { return simulatorModelIdentifier }
var systemInfo = utsname()
uname(&systemInfo)
return withUnsafeMutablePointer(to: &systemInfo.machine) {
ptr in String(cString: UnsafeRawPointer(ptr).assumingMemoryBound(to: CChar.self))
}
}
public static var model: DeviceModel {
// Thanks https://stackoverflow.com/a/26962452/5928180
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafeMutablePointer(to: &systemInfo.machine) {
ptr in String(cString: UnsafeRawPointer(ptr).assumingMemoryBound(to: CChar.self))
}
// Thanks https://stackoverflow.com/a/33495869/5928180
if modelCode == "i386" || modelCode == "x86_64" {
if let simulatorModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"], let model = DeviceModel.Model(modelCode: simulatorModelCode) {
return DeviceModel.simulator(model)
} else if let simulatorModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
return DeviceModel.unrecognizedSimulator(simulatorModelCode)
} else {
return DeviceModel.unrecognized(modelCode)
}
} else if let model = DeviceModel.Model(modelCode: modelCode) {
return DeviceModel.real(model)
} else {
return DeviceModel.unrecognized(modelCode)
}
}
public static var modelType: DeviceModel.Model? {
return UIDevice.model.model
}
public static func isDevice(ofType model: DeviceModel.Model) -> Bool {
return UIDevice.modelType == model
}
}
public enum DeviceModel {
case simulator(Model)
case unrecognizedSimulator(String)
case real(Model)
case unrecognized(String)
public enum Model: String {
case iPod1 = "iPod 1"
case iPod2 = "iPod 2"
case iPod3 = "iPod 3"
case iPod4 = "iPod 4"
case iPod5 = "iPod 5"
case iPad2 = "iPad 2"
case iPad3 = "iPad 3"
case iPad4 = "iPad 4"
case iPhone4 = "iPhone 4"
case iPhone4S = "iPhone 4S"
case iPhone5 = "iPhone 5"
case iPhone5S = "iPhone 5S"
case iPhone5C = "iPhone 5C"
case iPadMini1 = "iPad Mini 1"
case iPadMini2 = "iPad Mini 2"
case iPadMini3 = "iPad Mini 3"
case iPadAir1 = "iPad Air 1"
case iPadAir2 = "iPad Air 2"
case iPadPro9_7 = "iPad Pro 9.7\""
case iPadPro9_7_cell = "iPad Pro 9.7\" cellular"
case iPadPro10_5 = "iPad Pro 10.5\""
case iPadPro10_5_cell = "iPad Pro 10.5\" cellular"
case iPadPro12_9 = "iPad Pro 12.9\""
case iPadPro12_9_cell = "iPad Pro 12.9\" cellular"
case iPhone6 = "iPhone 6"
case iPhone6plus = "iPhone 6 Plus"
case iPhone6S = "iPhone 6S"
case iPhone6Splus = "iPhone 6S Plus"
case iPhoneSE = "iPhone SE"
case iPhone7 = "iPhone 7"
case iPhone7plus = "iPhone 7 Plus"
case iPhone8 = "iPhone 8"
case iPhone8plus = "iPhone 8 Plus"
case iPhoneX = "iPhone X"
init?(modelCode: String) {
switch modelCode {
case "iPod1,1": self = .iPod1
case "iPod2,1": self = .iPod2
case "iPod3,1": self = .iPod3
case "iPod4,1": self = .iPod4
case "iPod5,1": self = .iPod5
case "iPad2,1": self = .iPad2
case "iPad2,2": self = .iPad2
case "iPad2,3": self = .iPad2
case "iPad2,4": self = .iPad2
case "iPad2,5": self = .iPadMini1
case "iPad2,6": self = .iPadMini1
case "iPad2,7": self = .iPadMini1
case "iPhone3,1": self = .iPhone4
case "iPhone3,2": self = .iPhone4
case "iPhone3,3": self = .iPhone4
case "iPhone4,1": self = .iPhone4S
case "iPhone5,1": self = .iPhone5
case "iPhone5,2": self = .iPhone5
case "iPhone5,3": self = .iPhone5C
case "iPhone5,4": self = .iPhone5C
case "iPad3,1": self = .iPad3
case "iPad3,2": self = .iPad3
case "iPad3,3": self = .iPad3
case "iPad3,4": self = .iPad4
case "iPad3,5": self = .iPad4
case "iPad3,6": self = .iPad4
case "iPhone6,1": self = .iPhone5S
case "iPhone6,2": self = .iPhone5S
case "iPad4,1": self = .iPadAir1
case "iPad4,2": self = .iPadAir2
case "iPad4,4": self = .iPadMini2
case "iPad4,5": self = .iPadMini2
case "iPad4,6": self = .iPadMini2
case "iPad4,7": self = .iPadMini3
case "iPad4,8": self = .iPadMini3
case "iPad4,9": self = .iPadMini3
case "iPad6,3": self = .iPadPro9_7
case "iPad6,11": self = .iPadPro9_7
case "iPad6,4": self = .iPadPro9_7_cell
case "iPad6,12": self = .iPadPro9_7_cell
case "iPad6,7": self = .iPadPro12_9
case "iPad6,8": self = .iPadPro12_9_cell
case "iPad7,3": self = .iPadPro10_5
case "iPad7,4": self = .iPadPro10_5_cell
case "iPhone7,1": self = .iPhone6plus
case "iPhone7,2": self = .iPhone6
case "iPhone8,1": self = .iPhone6S
case "iPhone8,2": self = .iPhone6Splus
case "iPhone8,4": self = .iPhoneSE
case "iPhone9,1": self = .iPhone7
case "iPhone9,2": self = .iPhone7plus
case "iPhone9,3": self = .iPhone7
case "iPhone9,4": self = .iPhone7plus
case "iPhone10,1": self = .iPhone8
case "iPhone10,2": self = .iPhone8plus
case "iPhone10,3": self = .iPhoneX
case "iPhone10,6": self = .iPhoneX
default: return nil
}
}
}
public var name: String {
switch self {
case .simulator(let model): return "Simulator[\(model.rawValue)]"
case .unrecognizedSimulator(let s): return "UnrecognizedSimulator[\(s)]"
case .real(let model): return model.rawValue
case .unrecognized(let s): return "Unrecognized[\(s)]"
}
}
public var model: DeviceModel.Model? {
switch self {
case .simulator(let model): return model
case .real(let model): return model
case .unrecognizedSimulator(_): return nil
case .unrecognized(_): return nil
}
}
}
答案 19 :(得分：2)
我的简单解决方案按设备分组，并支持iPhone 8中的新设备iPhone X和Swift 3：
public extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
switch identifier {
case "iPhone3,1", "iPhone3,2", "iPhone3,3", "iPhone4,1":
return "iPhone 4"
case "iPhone5,1", "iPhone5,2", "iPhone5,3", "iPhone5,4", "iPhone6,1", "iPhone6,2", "iPhone8,4":
return "iPhone 5"
case "iPhone7,2", "iPhone8,1", "iPhone9,1", "iPhone9,3", "iPhone10,1", "iPhone10,4":
return "iPhone 6,7,8"
case "iPhone7,1", "iPhone8,2", "iPhone9,2", "iPhone9,4", "iPhone10,2", "iPhone10,5":
return "iPhone Plus"
case "iPhone10,3", "iPhone10,6":
return "iPhone X"
case "i386", "x86_64":
return "Simulator"
default:
return identifier
}
}
}
并使用：
switch UIDevice.current.modelName {
case "iPhone 4":
case "iPhone 5":
case "iPhone 6,7,8":
case "iPhone Plus":
case "iPhone X":
case "Simulator":
default:
}
答案 20 :(得分：1)
使用Swift＆＃39; switch-case＆＃39;：
func platformString() -> String {
var devSpec: String
switch platform() {
case "iPhone1,2": devSpec = "iPhone 3G"
case "iPhone2,1": devSpec = "iPhone 3GS"
case "iPhone3,1": devSpec = "iPhone 4"
case "iPhone3,3": devSpec = "Verizon iPhone 4"
case "iPhone4,1": devSpec = "iPhone 4S"
case "iPhone5,1": devSpec = "iPhone 5 (GSM)"
case "iPhone5,2": devSpec = "iPhone 5 (GSM+CDMA)"
case "iPhone5,3": devSpec = "iPhone 5c (GSM)"
case "iPhone5,4": devSpec = "iPhone 5c (GSM+CDMA)"
case "iPhone6,1": devSpec = "iPhone 5s (GSM)"
case "iPhone6,2": devSpec = "iPhone 5s (GSM+CDMA)"
case "iPhone7,1": devSpec = "iPhone 6 Plus"
case "iPhone7,2": devSpec = "iPhone 6"
case "iPod1,1": devSpec = "iPod Touch 1G"
case "iPod2,1": devSpec = "iPod Touch 2G"
case "iPod3,1": devSpec = "iPod Touch 3G"
case "iPod4,1": devSpec = "iPod Touch 4G"
case "iPod5,1": devSpec = "iPod Touch 5G"
case "iPad1,1": devSpec = "iPad"
case "iPad2,1": devSpec = "iPad 2 (WiFi)"
case "iPad2,2": devSpec = "iPad 2 (GSM)"
case "iPad2,3": devSpec = "iPad 2 (CDMA)"
case "iPad2,4": devSpec = "iPad 2 (WiFi)"
case "iPad2,5": devSpec = "iPad Mini (WiFi)"
case "iPad2,6": devSpec = "iPad Mini (GSM)"
case "iPad2,7": devSpec = "iPad Mini (GSM+CDMA)"
case "iPad3,1": devSpec = "iPad 3 (WiFi)"
case "iPad3,2": devSpec = "iPad 3 (GSM+CDMA)"
case "iPad3,3": devSpec = "iPad 3 (GSM)"
case "iPad3,4": devSpec = "iPad 4 (WiFi)"
case "iPad3,5": devSpec = "iPad 4 (GSM)"
case "iPad3,6": devSpec = "iPad 4 (GSM+CDMA)"
case "iPad4,1": devSpec = "iPad Air (WiFi)"
case "iPad4,2": devSpec = "iPad Air (Cellular)"
case "iPad4,4": devSpec = "iPad mini 2G (WiFi)"
case "iPad4,5": devSpec = "iPad mini 2G (Cellular)"
case "iPad4,7": devSpec = "iPad mini 3 (WiFi)"
case "iPad4,8": devSpec = "iPad mini 3 (Cellular)"
case "iPad4,9": devSpec = "iPad mini 3 (China Model)"
case "iPad5,3": devSpec = "iPad Air 2 (WiFi)"
case "iPad5,4": devSpec = "iPad Air 2 (Cellular)"
case "i386": devSpec = "Simulator"
case "x86_64": devSpec = "Simulator"
default: devSpec = "Unknown"
}
return devSpec
}
答案 21 :(得分：1)
如果您不希望每次Apple向设备系列添加新模型时都不断更新代码，请使用以下方法仅返回模型代码。
func platform() -> String {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafeMutablePointer(&systemInfo.machine) {
ptr in String.fromCString(UnsafePointer<CChar>(ptr))
}
return String.fromCString(modelCode!)!
}
答案 22 :(得分：1)
extension UIDevice {
public static let hardwareModel: String = {
var path = [CTL_HW, HW_MACHINE]
var n = 0
sysctl(&path, 2, nil, &n, nil, 0)
var a: [UInt8] = .init(repeating: 0, count: n)
sysctl(&path, 2, &a, &n, nil, 0)
return .init(cString: a)
}()
}
UIDevice.hardwareModel // → iPhone9,3
答案 23 :(得分：0)
struct DeviceType {
static let IS_IPHONE_4_OR_LESS = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH < 568
static let IS_IPHONE_5 = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 568
static let IS_IPHONE_6 = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 667
static let IS_IPHONE_6P = UIDevice.current.userInterfaceIdiom == .phone && Constants.SCREEN_MAX_LENGTH == 736
static let IS_IPAD = UIDevice.current.userInterfaceIdiom == .pad && Constants.SCREEN_MAX_LENGTH == 1024
}
答案 24 :(得分：0)
struct utsname systemInfo;
uname(&systemInfo);
NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
encoding:NSUTF8StringEncoding];
答案 25 :(得分：0)
请谨慎使用private API -[UIDevice _deviceInfoForKey:]，Apple不会拒绝您，
// works on both simulators and real devices, iOS 8 to iOS 12
NSString *deviceModelName(void) {
// For Simulator
NSString *modelName = NSProcessInfo.processInfo.environment[@"SIMULATOR_DEVICE_NAME"];
if (modelName.length > 0) {
return modelName;
}
// For real devices and simulators, except simulators running on iOS 8.x
UIDevice *device = [UIDevice currentDevice];
NSString *selName = [NSString stringWithFormat:@"_%@ForKey:", @"deviceInfo"];
SEL selector = NSSelectorFromString(selName);
if ([device respondsToSelector:selector]) {
#pragma clang diagnostic push
#pragma clang diagnostic ignored "-Warc-performSelector-leaks"
modelName = [device performSelector:selector withObject:@"marketing-name"];
#pragma clang diagnostic pop
}
return modelName;
}
在模拟器上运行的NSProcessInfo.processInfo.environment包含一个名为“ SIMULATOR_CAPABILITIES”的密钥，其值为plist文件。然后打开plist文件，您将获得模型名称的关键字“ marketing-name”。
答案 26 :(得分：0)
Swift 4：仅输出您当前的iPhone设备型号
import UIKit
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
@IBOutlet weak var lblVersion: UILabel!
override func viewWillAppear(_ animated: Bool) {
super.viewWillAppear(animated)
let systemVersion_ = UIDevice.current.systemVersion
lblVersion.text = systemVersion_
}
}
Apple Dev Docs : https://developer.apple.com/documentation/uikit/uidevice/1620043-systemversion
答案 27 :(得分：0)
为此有一个助手library。
快速5
pod'DeviceKit'，'〜> 2.0'
Swift 4.0-Swift 4.2
pod'DeviceKit'，'〜> 1.3'
如果您只是想确定模型并做相应的事情。
您可以这样使用：
let isIphoneX = Device().isOneOf([.iPhoneX, .simulator(.iPhoneX)])
在函数中：
func isItIPhoneX() -> Bool {
let device = Device()
let check = device.isOneOf([.iPhoneX, .iPhoneXr , .iPhoneXs , .iPhoneXsMax ,
.simulator(.iPhoneX), .simulator(.iPhoneXr) , .simulator(.iPhoneXs) , .simulator(.iPhoneXsMax) ])
return check
}
答案 28 :(得分：0)
对于swift4.0及更高版本，使用以下代码：
ModuleC答案 29 :(得分：0)
所有答案都很好。得到一些信息后，我创建了THIS GIST
它包含 DeviceModel ，它是“核心”（无UIKit依赖）模块的一部分。它甚至可以用作模型。
可以从另一个“核心”模块组件中使用它，
struct DeviceHelper {
static var specificModelType: DeviceModel {
var systemInfo = utsname()
uname(&systemInfo)
let modelCode = withUnsafePointer(to: &systemInfo.machine) {
$0.withMemoryRebound(to: CChar.self, capacity: 1) {
ptr in String.init(validatingUTF8: ptr)
}
}
let modelType = DeviceModel(modelCode: modelCode ?? "")
if modelType == .simulator {
return .simulator
// UP TO YOU
// if let simModelCode = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] {
// return DeviceModel(modelCode: simModelCode)
// }
} else {
return modelType
}
}
或者通过类似“ UI”模块的组件：
extension UIDevice {
static var specificModelType: DeviceModel {
DeviceHelper.specificModelType
}
}