Question

我正在使用Spring工具套件在spring MVC项目和spring数据中工作，我希望将日期参数传递给本机查询，到目前为止我已经这样做了。

我在扩展JpaRepository

的接口中的查询方法

 @Query(value  = 
            "SELECT "
                + "a.name, a.lastname
            + "FROM "
                + "person  a, "
                + "myTable b "
            + "WHERE "
            + "a.name= ?1' "
            + "AND a.birthday = ?2 ",
         nativeQuery = true)
    public ArrayList<Object> personInfo(String name, String dateBirthDay);

实现此接口定义的方法：

public ArrayList<Object> getPersonsList(String name, String dateBirthDay) {

            ArrayList<Object> results= null;

            results= serviceAutowiredVariable.personInfo(name, dateBirthDay);

            return results;
        }

这就是我从控制器类中调用它的方式。

personsList= _serviceAutowiredVariable.getPersonsList("Jack", "TO_DATE('01-08-2013', 'DD-MM-YYYY')" );

我认为在这一行"AND a.birthday = ?2 "中，?2等于此字符串TO_DATE('01-08-2013', 'DD-MM-YYYY')

但是当我运行代码时出现此错误

    [Request processing failed; nested exception is org.springframework.orm.jpa.JpaSystemException: org.hibernate.exception.DataException: could not extract ResultSet; nested exception is javax.persistence.PersistenceException: org.hibernate.exception.DataException: could not extract ResultSet] root cause
java.sql.SQLDataException: ORA-01858: a non-numeric character was found where a numeric was expected

ERROR: org.hibernate.engine.jdbc.spi.SqlExceptionHelper - ORA-01858: a non-numeric character was found where a numeric was expected

Answer 1

你可以使用这样的结构：

import org.springframework.data.repository.query.Param;
...

@Query(value  = 
    " SELECT a.id, a.lastname FROM person a" + 
    " WHERE a.name = :name AND a.birthday = :date ", nativeQuery = true)
public List<Object[]> getPersonInfo(
    @Param("name") String name, 
    @Param("date") Date date);

Spring Data JPA如何传递日期参数

1 个答案: