Question

如何计算两个日期之间晚上9点的次数？

dt_start_time = "2014-09-23 11:00:00"
dt_end_time   = "2014-09-24 12:00:00"

预期输出为1

dt_start_time = "2014-09-24 09:00:00"
dt_end_time   = "2014-09-24 22:00:00"

预期产出1

dt_start_time = "2014-09-24 09:00:00"
dt_end_time   = "2014-09-26 12:00:00"

预期产出2

Answer 1

您可以通过将两个日期之间的时差转换为天数来实现此目的，如果日期范围因为收尾而错过额外的9点，则可以额外增加一天

dt_start_time = "2014-09-23 11:00:00"
dt_end_time = "2014-09-24 23:00:00"

format = "%Y-%m-%d %H:%M:%S"

from datetime import datetime as dt

st = dt.strptime(dt_start_time, format)
end = dt.strptime(dt_end_time, format)

count = (end - st).days
if st.hour < 21 and end.hour >= 21:
    count += 1
print count

计算python中两个日期之间的晚上9点

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