我创建了以下Toast通知
ToastTemplateType toastType = ToastTemplateType.ToastText02;
XmlDocument toastXml = ToastNotificationManager.GetTemplateContent(toastType);
XmlNodeList toastTextElement = toastXml.GetElementsByTagName("text");
toastTextElement[0].AppendChild(toastXml.CreateTextNode("Hello C# Corner"));
toastTextElement[1].AppendChild(toastXml.CreateTextNode("I am poping you from a Winmdows Phone App"));
IXmlNode toastNode = toastXml.SelectSingleNode("/toast");
((XmlElement)toastNode).SetAttribute("duration", "long");
((XmlElement)toastNode).SetAttribute("type", "Employee");
((XmlElement)toastNode).SetAttribute("launch", "<cat state='angry'><facebite state='true' /></cat>");
ToastNotification toast = new ToastNotification(toastXml);
ToastNotificationManager.CreateToastNotifier().Show(toast);
我想知道如何访问类型属性。
当我尝试使用下面的代码时,它返回null
var att = toast.Content.Attributes;
答案 0 :(得分:1)
调试显示答案。
var att = toast.Content.ChildNodes[0].Attributes[1].NodeValue;
答案 1 :(得分:0)
var att =
toast.Content
.SelectSingleNode("/toast/visual/binding")
.SelectNodes("text")[0].InnerText