编写一个名为containsLetter的函数，该函数标识列表中包含指定字母的所有字符串，并返回这些字符串的列表

Question

searchLetter = str(input("Enter a Letter: ")
hulkLine= ["you", "wouldn't", "like", "me", "when", "i'm", "angry"]                   
def containsLetter(searchLetter, hulkLine):
    for x in range(hulkLine -1):
            if hulkLine[x] == 't':

我发布了以下函数的正确输出。

函数containsLetter()有两个参数：

1. 长度为1的字符串aLetter
2. 字符串列表strList

例如，以下是正确的输出：

>>> hulkLine = ["you", "wouldn't", "like", "me", "when", "i'm", "angry"] 
>>> searchLetter = 'i' 
>>> print(containsLetter(searchLetter, hulkLine)) 
>>> ["like", "i'm"]

Answer 1

这可以吗？

>>> def containsLetter(searchLetter, hulkLine):
...     return [x for x in hulkLine if searchLetter in x]
...
>>> containsLetter('i', hulkLine)
['like', "i'm"]
>>>

或

>>> filter(lambda x: searchLetter in x, hulkLine)
['like', "i'm"]
>>>