Question

我有一个带有选择列表/正整数字段的模型类。

class AchievementDetails(models.Model, FillableModelWithLanguageVersion):
    ACADEMIC_ACHIEVEMENT = 1
    COMMERCIAL_ACHIEVEMENT = 2
    PERSONAL_ACHIEVEMENT = 3
    PROFESSIONAL_ACHIEVEMENT = 4
    SPORTING_ACHIEVEMENT = 5
    OTHER_ACHIEVEMENT_TYPE = 6

ACHIEVEMENT_TYPES = (
    (ACADEMIC_ACHIEVEMENT, _('Academic Details')),
    (COMMERCIAL_ACHIEVEMENT, _('Commercial Achievement')),
    (PERSONAL_ACHIEVEMENT, _('Personal Achievement')),
    (PROFESSIONAL_ACHIEVEMENT, _('Professional Achievement')),
    (SPORTING_ACHIEVEMENT, _('Sporting Achievement')),
    (OTHER_ACHIEVEMENT_TYPE, _('Other Achievement Type')),
)

....
achievement_type = models.PositiveIntegerField(choices=ACHIEVEMENT_TYPES)
....

在我的views.py中，我试图显示成就类型的选定文本。例如：学业成就

目前我只能显示所选的数值。例如：1

以下是我在views.py中的代码：

def achievement_details(request):
    ....
    for ad in achievement_details:
        ad.achievement_type_as_text = ad.achievement_type
    ....

返回ACHIEVEMENT_TYPES所选文字的正确代码是什么？

Answer 1

这就是答案：

https://docs.djangoproject.com/en/dev/ref/models/instances/#django.db.models.Model.get_FOO_display

因此，对于我的示例，语法将是：

def achievement_details(request):
....
for ad in achievement_details:
    ad.achievement_type_as_text = ad.get_achievement_type_dispay()
....

我希望这可以帮助别人。

Answer 2

由于你有一个元组列表，你想使用类似下面的

ACHIEVEMENT_TYPES = (
    (ACADEMIC_ACHIEVEMENT, 'Academic Details'),
    (COMMERCIAL_ACHIEVEMENT, 'Commercial Achievement'),
    (PERSONAL_ACHIEVEMENT, 'Personal Achievement'),
    (PROFESSIONAL_ACHIEVEMENT, 'Professional Achievement'),
    (SPORTING_ACHIEVEMENT, 'Sporting Achievement'),
    (OTHER_ACHIEVEMENT_TYPE, 'Other Achievement Type'),
)

result = [item for item in ACHIEVEMENT_TYPES if item[0] == ad.achievement_type]

ad.achievement_type_as_text = result[1]

django views.py - 显示正整数文本值

2 个答案: