Question

我无法在任何地方找到答案，这是一个新的错误。有人可以帮我说这句话：

<?php 
if ($db_ownrPlan == 'sell in a year or so' || 'get some info only no plans made yet'){
    echo "$TYmessage";
} elseif ($db_ownrPlan == 'sell soon' || 'sell in 3 to 6 months' || 'looking to buy this property'){
    echo "$TYmessage1";
} else {
    echo "$TYmessage2";
} 
?>

Answer 1

if (in_array($db_ownrPlan, 
   array('sell in a year or so', 'get some info only no plans made yet')))

等紧凑形式（没有检查速度）......

Answer 2

正确的语法是：

($db_ownrPlan == 'sell in a year or so' || $db_ownrPlan =='get some info only no plans made yet')

否则第二个条件只是字符串而不是比较。

Answer 3

这是你想要做的：

<?php 
if ($db_ownrPlan == 'sell in a year or so' || $db_ownrPlan == 'get some info only no plans made yet'){
    echo "$TYmessage";
} elseif ($db_ownrPlan == 'sell soon' || $db_ownrPlan == 'sell in 3 to 6 months' || $db_ownrPlan == 'looking to buy this property'){
    echo "$TYmessage1";
} else {
    echo "$TYmessage2";
} 
?>

在PHP和其他大多数语法相似的编程语言中，你可以比较这样的变量：

VAR == value OR VAR == otherValue

正确使用AND OR（||＆amp;＆amp;）和两个字符串值

3 个答案: