Question

// program that split a string and stock words in a vector array

#include <iostream>
#include <string>
#include <vector>

using namespace std;

int main()
{
cout << "substring using vector test\n" << endl;

bool reste(1);
vector<string> mots;   // our vector 'word' mots is french vector
size_t found(-1);      // init at - 1 because i need to wirte +1 to start at 0 
int prevFound(-1);     // same explanation, prevFound meaning previous found
string chaine ("let's test this piece of code");  

do
{
 found = chaine.find(" ",found+1);  // looking for the first space encountered


if (found!=string::npos)   // if a space is found..
{
   cout << "\nSpace found at: " << found << '\n';  // position of the first space
   mots.push_back(chaine.substr(prevFound+1,found-prevFound)); // add a 'case' in vector and substract the word //
   prevFound = found;  // stock the actual pos in the previous for the next loop


}
if (found==string::npos)    // if no space is remaining, extract last word
{
   cout << "\nlast word\n\n" << endl;
   mots.push_back(chaine.substr(prevFound+1,found-prevFound));
   reste = 0;
}

}while (reste);   


cout << "\nraw sentence : " << chaine << endl;

unsigned int taille = mots.size();  // taille meaning size
cout << "number of words" << taille << "\n" << endl;

for (int i(0); i<=taille; i++)  // loop showing the extracted words
{
cout << mots[i] << '\n';
}
return 0;
}

感谢您的时间。我试图翻译用我的母语编码的大部分代码，我可能在我的expalanations上无关紧要。我现在已经在网上学习了两个星期的c ++，非常好。

我只是想知道为什么我的代码编译和执行但最后崩溃，我的代码用静态arry做得很好。也许我需要一个集装箱？如果是，有人可以使用std :: set更正我的代码。提前谢谢。

Answer 1

您的程序有未定义的行为，因为您访问了矢量越界。

改变这个：

for (int i(0); i<=taille; i++)

致：

for (int i(0); i<taille; i++)

或更简单：

for (auto& mot : mots)  
{
    cout << mot << '\n';
}

我的代码编译，执行但最后程序崩溃

1 个答案: