在初始化jquery.panzoom时,我试图弄清楚如何制作比浏览器窗口(2000x2800px)更大的图像。我需要图像来调整自身大小,使其适合容器的高度。
看看这个jsFiddle:http://jsbin.com/raxejirubayu/1/edit?html,css,js,output
任何有使用panzoom经验的人都可以帮助我吗?虚拟啤酒和高产品作为回报。
答案 0 :(得分:2)
我通过编写这个javascript代码解决了这个问题,它基本上根据图像大小和容器大小计算缩放和平移参数,并应用转换,使图像被拉伸到容器边界。
Javascript文件
$(document).ready(function(){
$panzoom = $(".cimage").panzoom();
//Wait for the image to load
$('.cimage').load(function(){
//Get container and image
var image = $('.cimage');
var container = $('.image-container');
//Get container dimensions
var container_height = container.height();
var container_width = container.width();
//Get image dimensions
var image_height = image.height();
var image_width = image.width();
//Calculate the center of image since origin is at x:50% y:50%
var image_center_left = image_width / 2.0;
var image_center_top = image_height / 2.0;
//Calculate scaling factor
var zoom_factor;
//Check to determine whether to stretch along width or heigh
if(image_height > image_width)
zoom_factor = container_height / image_height;
else
zoom_factor = container_width / image_width;
//Zoom by zoom_factor
$panzoom.panzoom("zoom", zoom_factor, {animate: false});
//Calculate new image dimensions after zoom
image_width = image_width * zoom_factor;
image_height = image_height * zoom_factor;
//Calculate offset of the image after zoom
var image_offset_left = image_center_left - (image_width / 2.0);
var image_offset_top = image_center_top - (image_height / 2.0);
//Calculate desired offset for image
var new_offset_left = (container_width - image_width) / 2.0;
var new_offset_top = (container_height - image_height) / 2.0;
//Pan to set desired offset for image
var pan_left = new_offset_left - image_offset_left;
var pan_top = new_offset_top - image_offset_top;
$panzoom.panzoom("pan", pan_left, pan_top);
});
});
HTML文件
<div class="image-container">
<img class='cimage' src="abc.jpg'/>
</div>
它沿着宽度或高度拉伸,取决于图像方向(纵向或横向),但如果您只想沿高度拉伸,则需要更换
if(image_height > image_width)
zoom_factor = container_height / image_height;
else
zoom_factor = container_width / image_width;
与
zoom_factor = container_height / image_height;
但我建议反对它,因为它无法处理风景图像。