我的GridView中有以下ASP.net按钮:
<asp:Button UseSubmitBehavior="false" runat="server" ID="btnShow" CssClass="btnSearch" Text="View All" CommandName="ViewAll" OnCommand="btnShow_Command" CommandArgument='<%#((GridViewRow)Container).RowIndex%>' />
代码隐藏是:
protected void btnShow_Command(object sender, CommandEventArgs e)
{
int index = 0;
if (e.CommandName == "ViewAll")
{
index = Convert.ToInt32(e.CommandArgument);
DataTable cacheTable = HttpContext.Current.Cache["ResultsTable"] as DataTable;
string column = cacheTable.Rows[index].Field<string>("Guideline");
string test = BookingResults.Rows[index].Cells[7].Text;
string html = HttpUtility.HtmlDecode(column);
ResultsDiv.InnerHtml = html;
}
}
ResultsDiv使用JQuery弹出窗口显示:
//CONTROLLING EVENTS IN jQuery
$(document).ready(function () {
//Click the button event!
$(".btnSearch").click(function (e) {
alert($(this).val() + " Clicked");
e.preventDefault();
//centering with css
centerPopup();
//load popup
loadPopup();
});
});
当我导航到该页面时,生成的HTML看起来如下(列中有多个行具有相同的按钮):
<input type="button" name="ctl00$ctl33$g_36ed1b14_1f08_43fb_8099_eb3423a33ed9$BookingResults$ctl224$btnShow" value="View All" onclick="javascript:WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions("ctl00$ctl33$g_36ed1b14_1f08_43fb_8099_eb3423a33ed9$BookingResults$ctl224$btnShow", "", true, "", "", false, true))" id="ctl00_ctl33_g_36ed1b14_1f08_43fb_8099_eb3423a33ed9_BookingResults_ctl224_btnShow" class="btnSearch" />
现在发生了什么,当我点击View All
按钮显示警报时,当我点击确定时,它会显示弹出一瞬间并刷新页面。
如何修改代码隐藏/ JQuery以便我可以单击任何按钮,它会显示警报并每次显示弹出窗口而不进行回发?
答案 0 :(得分:-1)
我认为即使在警报之前你需要做的第一件事是e.preventDefault();
//CONTROLLING EVENTS IN jQuery
$(document).ready(function () {
//Click the button event!
$(".btnSearch").click(function (e) {
e.preventDefault();
e.stopproPagation();
alert($(this).val() + " Clicked");
//centering with css
centerPopup();
//load popup
loadPopup();
});
});
正如我认为警报让事件首先执行默认作业。