Question

我知道如何在表中存储一条简单的JSON消息，但是如果我生成一个JSON数组，如何在这个表中轻松存储我的数据？例如：

[{＆＃34; ID＆＃34;：0，＆＃34;数据1＆＃34; 123＆＃34;数据2＆＃34;：＆＃34;字符串1＆＃34;＆＃34;时间戳＆＃34;：＆＃34; /日期（-62135596800000-0000）/＆＃34;}，{＆＃34; ID＆＃34;：0，＆＃34;数据1＆＃34;：456，＆＃34;数据2＆＃34;：＆＃34;字符串2＆＃34;＆＃34;时间戳＆＃34;：＆＃34; /日期（-62135596800000-0000）/＆＃34;}]

我试过这样的事情，但~~它没有工作~~它没有编译：

public class Table1
{
    public List<Table1> Table1LIST{ get; set; }

    [AutoIncrement]
    public int ID { get; set; } 
    public int Data1{ get; set; }
    public string Data2{ get; set; }
    public DateTime Timestamp { get; set; }
}

// Add Table1 via POST
[Route("/Table1ADD", Verbs = "POST")]
public class Table1 ADD
{
    public int ID { get; set; } 
    public int Data1{ get; set; }
    public string Data2{ get; set; }
    public DateTime Timestamp { get; set; }
}

// Add multi Table1 via POST
[Route("/Table1ADDMulti", Verbs = "POST")]
public class Table1 ADDMulti
{
    public List<Table1 > Table1LIST { get; set; }
}

    // Store JSON array
    public object Post(Table1Multi request)
    {
        var data =new Table1()
        {
            Table1LIST = request.Table1LIST
        };

        CRUDFunctions CRUD = new CRUDFunctions(Db);
        return CRUD.AddData(data);
    }

我使用函数insert来存储我的数据（CRUD.AddData（））。此函数指定可以同时存储多个行。

这个想法是避免发送多条消息。提前致谢

Answer 1

您非常接近，除非您不应向List<Table1>添加Table1。而是创建Table1，如下所示，并创建一个简单的DTO，如Table1Multiple来处理多个值。

[Route("/Table1","POST")]
public class Table1 : IReturn<int>
{
    [AutoIncrement]
    public int ID { get; set; } 
    public int Data1 { get; set; }
    public string Data2 { get; set; }
    public DateTime Timestamp { get; set; }
}

[Route("/Table1/Multi","POST")]
public class Table1Multiple : IReturn<List<int>>
{
    public List<Table1> Values { get; set; }
}

在服务中，您应该重复使用用于存储单个记录的代码，并简单地迭代Table1 Values列表。

class TestService : Service
{
    // Stores a single Table1 record
    public int Post(Table1 request)
    {
        // Add your method to store a single record
        var CRUD = new CRUDFunctions(Db);
        return CRUD.AddData(request); // Return the ID of the created record
    }

    // Stores multiple Table1 records
    public List<int> Post(Table1Multiple request)
    {
        // Return a list of the record Ids
        var result = new List<int>();

        // Process each request, through the single record code
        foreach(var value in request.Values)
            result.Add(Post(value));

        return result;
    }
}

解决您未填充的DTO

I don't get anything in "request" in debug mode.

你有两个选择。您可以更改请求以使用属性values

{values:[{"ID":0,"Data1":123,"Data2":"String1","Timestamp":"/Date(-62135596800000-0000)/"},
         {"ID":0,"Data1":456,"Data2":"String2","Timestamp":"/Date(-62135596800000-0000)/"}]}

或您可以将请求DTO更改为从List<Table1>扩展而来：

// 
[Route("/Table1/Multi","POST")]
public class Table1Multiple : List<Table1>, IReturn<List<int>>
{
}

然后修改服务，使其显示var value in request而不是var value in request.Values

class TestService : Service
{
    // Stores a single Table1 record
    public int Post(Table1 request)
    {
        // Add your method to store a single record
        var CRUD = new CRUDFunctions(Db);
        return CRUD.AddData(request); // Return the ID of the created record
    }

    // Stores multiple Table1 records
    public List<int> Post(Table1Multiple request)
    {
        // Return a list of the record Ids
        var result = new List<int>();

        // Process each request, through the single record code
        foreach(var value in request) // Collection changed here
            result.Add(Post(value));

        return result;
    }
}

如何使用ServiceStack存储JSON数组？

1 个答案:

解决您未填充的DTO