Question

我有一个查询从5个表中检索信息。它们之间的关系如附图所示。我创建了一个查询来做到这一点，到目前为止一直很好。问题是每个用户在“PROFISSIONAL_PORCENTAGEM”表中可以有1个或多个条目。我的查询是检索所有这些。我希望最后一个基于日期字段“PROFISSIONAL_PORCENTAGEM_DATA”。我已经对这个问题进行了研究，当我们只使用一个表时，“检索每个id的最新内容”的解决方案是相同的，请参阅此处的示例MySQL - Selecting the most recent post by each of the 10 most recent authors。但在这种情况下，我有5个表。我不知道该怎么做。任何想法都将不胜感激。

SELECT
  PP.PROFISSIONAL_PORCENTAGEM_Pk,
  UST.USER_NAME, 
  ADDR.ADDRESS_NOME, 
  ADDR.ADDRESS_ATIVO,
  PA.PROFESSIONAL_ADDRSS_PK, 
  PP.PROFISSIONAL_PORCENTAGEM_PORCENT,
  PP.PROFISSIONAL_PORCENTAGEM_FK_CLINICA,
  PP.PROFISSIONAL_PORCENTAGEM_DATA

FROM 
  profissional_porcentagem AS PP
  RIGHT JOIN professional_addrss AS PA
    ON(PP.PROFISSIONAL_PORCENTAGEM_FK_CLINICA=PA.PROFESSIONAL_ADDRSS_PK)

  INNER JOIN address ADDR
    ON(PA.PROFESSIONAL_ADDRSS_FKADDRSS=ADDR.ADDRESS_Pk)

  INNER JOIN professional PF
    ON(PA.PROFESSIONAL_ADDRSS_FKPROFESSIONAL=PF.PROFESSIONAL_Pk)

  INNER JOIN usert AS UST
    ON(PF.PROFESSIONAL_FKUSER=UST.USER_Pk)

WHERE UST.USER_Pk=3
AND ADDR.ADDRESS_ATIVO=1;

抱歉，我需要10个声望来附加图片！这是图片链接http://imgur.com/ZP3OdeX

Answer 1

好吧，最后我找到了解决方案。只需将此代码添加到SQL查询的末尾：

AND PP.PROFISSIONAL_PORCENTAGEM_Pk = (
SELECT t2.PROFISSIONAL_PORCENTAGEM_Pk FROM profissional_porcentagem as t2
    where t2.PROFISSIONAL_PORCENTAGEM_FK_CLINICA = PP.PROFISSIONAL_PORCENTAGEM_FK_CLINICA 
    order by t2.PROFISSIONAL_PORCENTAGEM_Pk desc limit 1
)

然后我们会像这样得到整个查询：

SELECT
PP.PROFISSIONAL_PORCENTAGEM_Pk,
UST.USER_NAME, 
ADDR.ADDRESS_NOME, 
ADDR.ADDRESS_ATIVO,
PA.PROFESSIONAL_ADDRSS_PK, 
PP.PROFISSIONAL_PORCENTAGEM_PORCENT,
PP.PROFISSIONAL_PORCENTAGEM_FK_CLINICA,
PP.PROFISSIONAL_PORCENTAGEM_DATA

FROM 
profissional_porcentagem AS PP
RIGHT JOIN professional_addrss AS PA
    ON(PP.PROFISSIONAL_PORCENTAGEM_FK_CLINICA=PA.PROFESSIONAL_ADDRSS_PK)

INNER JOIN address ADDR
    ON(PA.PROFESSIONAL_ADDRSS_FKADDRSS=ADDR.ADDRESS_Pk)

INNER JOIN professional PF
    ON(PA.PROFESSIONAL_ADDRSS_FKPROFESSIONAL=PF.PROFESSIONAL_Pk)

INNER JOIN usert AS UST
    ON(PF.PROFESSIONAL_FKUSER=UST.USER_Pk)

WHERE UST.USER_Pk=3
AND ADDR.ADDRESS_ATIVO=1

AND PP.PROFISSIONAL_PORCENTAGEM_Pk = (
SELECT t2.PROFISSIONAL_PORCENTAGEM_Pk FROM profissional_porcentagem as t2
    where t2.PROFISSIONAL_PORCENTAGEM_FK_CLINICA =   PP.PROFISSIONAL_PORCENTAGEM_FK_CLINICA 
    order by t2.PROFISSIONAL_PORCENTAGEM_Pk desc limit 1
);

注意：我受到了这篇文章的启发Select row with most recent date per user

Mysql - 最近输入的每个id

1 个答案: