Question

所以我需要在python中拆分列表，我的txt文件如下所示：

  ip,user,password
  ip,user,passord

等等。我已经在列表中读过了，我可以拆分它，但我只会得到第一个ip。我希望能够将列表分成三个单独的列表，一个用于ip，用户和密码。到目前为止，这是我的代码：

def OpenFile():
   read = [line.strip() for line in open("People.txt" , 'r')
   return read

jh = OpenFile()
sp = [i.split(',',1)[0] for i in jh]

Answer 1

您可以按,拆分它们，然后将zip拆分列表拆分为

with open("People.txt" , 'r') as inFile:
   ips, users, passwords = zip(*[line.strip().split(",") for line in inFile])

现在，如果您打印变量，您将获得

print ips, users, passwords
('ip', 'ip') ('user', 'user') ('password', 'passord')

Answer 2

使用zip：

>>> lines = ['ip,user,password', 'ip,user,passord']
>>> rows = [line.strip().split(',') for line in lines]  # `lines` -> file object
>>> rows
[['ip', 'user', 'password'], ['ip', 'user', 'passord']]
>>> zip(*rows)  # Output will be different in Python 3.x
[('ip', 'ip'), ('user', 'user'), ('password', 'passord')]
>>> ip, user, password = zip(*rows)
>>> ip
('ip', 'ip')
>>> user
('user', 'user')
>>> password
('password', 'passord')

将python中的列表拆分为三个单独的列表

2 个答案: