活动记录查询接口。数数，加入＆amp;组

Question

我试图按喜欢的数量排序所有电影（即使他们还没喜欢）。我有以下工作sql语句：

      SELECT *, COUNT(case when movie_votes.like = 1 then 1 end) AS count_likes 
      FROM movies 
      LEFT OUTER JOIN movie_votes  
      ON movie_votes.movie_id = movies.id 
      GROUP BY movie_id 
      ORDER BY count_likes;

我想在我的控制器中实现它。到目前为止，我有：

      Movie.select("*, COUNT(case when 'movie_votes'.'like'=1 then 1 end) AS         count_likes").joins("LEFT OUTER JOIN 'movie_votes' ON 'movies'.'id'='movie_votes'.'movie_id'").group("'movie_id'")

哪些输出形成控制台：

     SELECT *, COUNT(case when 'movie_votes'.'like'=1 then 1 end AS count_likes FROM `movies` LEFT OUTER JOIN 'movie_votes' ON 'movie'.'id'='movie_votes'.'movie_id' GROUP BY 'movie_id'

和一个Mysql2 ::错误：你的SQL语法有错误; 我做错了没有语法吗？

Answer 1

对于那些可能会觉得有用的人：

    scope :order_by_likes_or_hates, lambda {|type| 
        select("*, COUNT(case when movie_votes.like=#{type} then 1 end) AS count_likes").joins("LEFT OUTER JOIN movie_votes ON movies.id=movie_votes.movie_id").group("movie_votes.movie_id").order("count_likes DESC")}

如果有人可以提供更干净的版本，请执行。