Question

我有一张付款表：

worker_id, amount, payed, date

表工人：

id, name, lname

我需要编写一个SQL，它将为我，7月，8月，9月提供名称，名称和总和。

Name | Lname | Sum_JUN | Sum_JULY | Sum_AUG | Sum_SEP

我正在尝试子查询但不能这样做。你能救我吗？

我创建了SQL（示例）。我将用PHP替换日期。

select w.name, w.lname,
sum(case when p.payed_date between '2014-06-01' and '2014-06-31' then p.amount else 0 end) `sum_june`,
sum(case when p.payed_date between '2014-07-01' and '2014-07-31' then p.amount else 0 end) `sum_july`,
sum(case when p.payed_date between '2014-08-01' and '2014-08-31' then p.amount else 0 end) `sum_august`,
sum(case when p.payed_date between '2014-09-01' and '2014-09-31' then p.amount else 0 end) `sum_september`,
sum(case when p.payed_date between '2014-10-01' and '2014-10-31' then p.amount else 0 end) `sum_november`
from worker w
left join worker_sum p on(w.id = p.worker_id)
group by w.id

Answer 1

您可以使用条件汇总作为您所需的金额，但这将为您提供表格中存在的所有年份的月份总和

select w.*,
sum(case when month(p.date) = 6 then p.amount else 0 end) `sum_june`,
sum(case when month(p.date) = 7 then p.amount else 0 end) `sum_july`,
sum(case when month(p.date) = 8 then p.amount else 0 end) `sum_august`,
sum(case when month(p.date) = 9 then p.amount else 0 end) `sum_september`
from workers w
left join payment p on(w.id = p.worker_id)
group by w.id

查询中的SQL子查询

1 个答案: