Question

我需要在给定的文本正文中匹配所有句子结尾符号，例如!，?，.（句点）等。

任何人都可以帮我解决这方面的正则表达式吗？

示例输入：

This is the f!!rst sentence! Is this the second one? The third sentence is here... And the fourth one!!

输出：

This is the f!!rst sentence Is this the second one The third sentence is here And the fourth one

Answer 1

您可能希望匹配任何内容（。*？），然后是句子结尾，后跟空格（\ s +）。从！，？和。是特殊字符，你需要远离它们。

例如

Pattern pattern = Pattern.compile("(.*?)[\\!\\?\\.]\\s+");
Matcher matcher = pattern.matcher("one two. three! four five? ");
while (matcher.find()) {
   System.out.println(matcher.group(1));
}

打印

one two
three
four five

Answer 2

[!?.]+(?=$|\s)

试试这个。你可以根据需要添加标记。替换为``。

参见演示。

http://regex101.com/r/lS5tT3/15

Answer 3

下面的正则表达式将匹配非单词字符（空格除外），后面必须跟一个空格字符或行锚点的结尾。 replaceAll函数有助于删除所有匹配的字符。

String s = "Blah! blah? blah... blah blah!!";
System.out.println(s.replaceAll("[^\\w\\s]+(?=\\s|$)", ""));

输出：

Blah blah blah blah blah

如果您只想删除单词中最后一个出现的?，.，!个字符，可以尝试以下代码。

String s = "This is the f!!rst sentence! Is this the second one? The third sentence is here... And the fourth one!!";
System.out.println(s.replaceAll("[!?.]+(?=\\s|$)", ""));

<强>输出：

This is the f!!rst sentence Is this the second one The third sentence is here And the fourth one

正则表达式匹配句末标记

3 个答案: