Question

我的表格中有几个gmail地址

foobarbaz@gmail.com 
foo.bar.baz@gmail.com
foobar.baz@gmail.com
foo.barbaz@gmail.com

我需要替换包含符号＆＃39;的地址gmail。＆＃39; 得到：

foobarbaz@gmail.com 
foobarbaz@gmail.com
foobarbaz@gmail.com
foobarbaz@gmail.com

我的查询不起作用

UPDATE voters set email
replace(substring(email, 1, LOCATE('@', email) -1), '.', '')
WHERE email REGEXP '@googlemail.com|@gmail.com'

请帮忙，谢谢！

Answer 1

您在@之前提取子字符串并替换了点，但在执行此操作后，您不会在@之后添加子字符串：

UPDATE voters 
SET email = CONCAT(replace(substring(email, 1, LOCATE('@', email) -1), '.', ''),
                   SUBSTRING(email, LOCATE('@', email)))
WHERE email REGEXP '@googlemail.com|@gmail.com'

DEMO

Answer 2

您可以使用substring_index＆amp;和＆amp ;; substring：

UPDATE table1
SET email = CONCAT (
        replace(substring_index(email, '@', 1), '.', '')
        ,substring(email, instr(email, '@'))
        )
WHERE substring_index(email, '@', -1) IN (
        'googlemail.com'
        ,'gmail.com'
        );

SQLFiddle

mysql从电子邮件地址中删除点

2 个答案: