Question

我有两张表正在关注

表名：stockIn

+----+-------------+------------+------------+        
| Id |  date       | Itemname   | stockInqty |    
+====+=============+============+============+
| 1  | 12/12/2014  | testitem   |  12        |
| 2  | 14/12/2014  | testitem11 |  20        |
+----+-------------+------------+------------+

表名：stockOut

+----+------------+-------------+-------------+
| Id | date       | Itemname    | stockOutqty |
+====+============+=============+=============+     
| 1  | 12/12/2014 | testitem    |  7          |
| 2  | 13/12/2014 | testitem11  |  15         |
+----+------------+-------------+-------------+

我需要在两个日期之间按照

的顺序组合testitem记录

+------------+-----------+-------------+-------------+
| date       | itemname  | stockInqty  | stockOutqty |
+============+===========+=============+=============+       
| 12/12/2014 | testitem  |  12         |   7         |
| 13/12/2014 | testitem  |  NIL        |   15        | 
| 14/12/2014 | testitem  |  20         |   NIL       |
+------------+-----------+-------------+-------------+

我收到了这样的查询

SELECT t1.`date`
     , t1.itemname
     , t1.stockInqty AS stockInqty
     , t2.stockInqty AS stockOutqty
FROM tbl1 t1 LEFT JOIN tbl2 t2 ON t1.`date` = t2.`date` 
                              AND t1.itemname = t2.itemname
UNION

SELECT t2.`date`
     , t2.itemname
     , t1.stockInqty AS stockInqty
     , t2.stockInqty AS stockOutqty
FROM tbl1 t1 RIGHT JOIN tbl2 t2 ON t1.`date` = t2.`date` 
                               AND t1.itemname = t2.itemname

查询结果将如下

+-------------+------------+------------+-------------+
|date         | itemname   | stockInqty | stockOutqty |    
+=============+============+============+=============+       
| 12/12/2014  | testitem   |      12    |   7         |   
| 14/12/2014  | testitem   |      20    |   NIL       |     
| 13/12/2014  | testitem   |      NIL   |   15        |
+-------------+------------+------------+-------------+

结果是根据第一张表数据排序的。

我需要根据日期对结果进行排序（即，第一条记录必须在12/12/2014上，第二条记录在13/14/2014上的14/12/2014三分之一。）

提前致谢。

Answer 1

按日期排序

尝试此操作

SELECT t1.`date`
         , t1.itemname
         , t1.stockInqty AS stockInqty
         , t2.stockInqty AS stockOutqty
    FROM tbl1 t1 LEFT JOIN tbl2 t2 ON t1.`date` = t2.`date` 
                                  AND t1.itemname = t2.itemname
    UNION

    SELECT t2.`date`
         , t2.itemname
         , t1.stockInqty AS stockInqty
         , t2.stockInqty AS stockOutqty
    FROM tbl1 t1 RIGHT JOIN tbl2 t2 ON t1.`date` = t2.`date` 
                                   AND t1.itemname = t2.itemname order by  date

Answer 2

使用此代码：

select date,itemname,stockInqty,stockOutqty from(
SELECT t1.date
 , t1.itemname
 , t1.stockInqty AS stockInqty
 , t2.stockInqty AS stockOutqty
 FROM tbl1 t1 LEFT JOIN tbl2 t2 ON t1.date = t2.date 
                          AND t1.itemname = t2.itemname
UNION

SELECT t2.date
 , t2.itemname
 , t1.stockInqty AS stockInqty
 , t2.stockInqty AS stockOutqty
FROM tbl1 t1 RIGHT JOIN tbl2 t2 ON t1.date = t2.date
                           AND t1.itemname = t2.itemname)
order by date

Answer 3

select * from
(
SELECT t1.date as sdate
     , t1.itemname
     , t1.stockInqty AS stockInqty
     , t2.stockInqty AS stockOutqty
FROM tbl1 t1 LEFT JOIN tbl2 t2 ON t1.`date` = t2.`date` 
                              AND t1.itemname = t2.itemname
UNION

SELECT t2.date as sdate
     , t2.itemname
     , t1.stockInqty AS stockInqty
     , t2.stockInqty AS stockOutqty
FROM tbl1 t1 RIGHT JOIN tbl2 t2 ON t1.`date` = t2.`date` 
                               AND t1.itemname = t2.itemname
) t
order by sdate

在sql中按日期排序

3 个答案: