Question

为什么日期与格式不匹配？

>>> import datetime
>>> dt1 = "9/1/2014 0:00"
>>> datetime.datetime.strptime(dt1, "%m/%d/%y %H:%M")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/_strptime.py", line 325, in _strptime
    (data_string, format))
ValueError: time data '9/1/2014 0:00' does not match format '%m/%d/%y %H:%M'

这一个要么：

>>> datetime.datetime.strptime(dt1, "%d/%m/%y %H:%M")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/_strptime.py", line 325, in _strptime
    (data_string, format))
ValueError: time data '9/1/2014 0:00' does not match format '%d/%m/%y %H:%M'

Answer 1

让我们打开http://strftime.org/并检查：

%m  Month as a zero-padded decimal number.

因此需要09，而不是9

%d  Day of the month as a zero-padded decimal number.

因此需要01，而不是1

%y  Year without century as a zero-padded decimal number.

因此需要14，而不是2014

%H  Hour (24-hour clock) as a zero-padded decimal number.

所以需要00，而不是0。

Answer 2

正确的语法是，

>>> from datetime import datetime
>>> datetime.strptime('2012-09-1 0:00', '%Y-%m-%d %H:%M')
datetime.datetime(2012, 9, 1, 0, 0)
>>>

日期与格式不匹配

2 个答案: