我刚开始学习php并在
创建了一个漂亮的小页面http://www.dowricks.com/index.php?route=information/yeast
我现在想将我的查询转换为准备好的陈述,并且没有运气就尝试了所有内容。
我要转换的部分如下 -
$q = 'SELECT yeast, rating, description, weblink
, image, sideimage
FROM dowdb_yeast_selector
WHERE fruit = "' . $_POST['fruit'] . '"
ORDER BY rating DESC';
$r = @mysqli_query ($dbc, $q); // Run the query.
// Present the results
echo '<table width="100 px" cellspacing="15" cellpadding="15">';// Table header:
echo '<tr bgcolor="green"><td colspan="5"><div class="yeast_heading" align="center"><em><b>The following yeasts are suitable for fermenting ' . $_POST['fruit'] . '</b></em></div></td></tr>';
echo '<tr bgcolor="green"><td align="left">Yeast</td><td align="left">Rating</td><td align="left">Description</td> <td></td><td></td></tr>';
// Fetch and print all the records....
$bg = '#676767';
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC))
{
$sideimage = $row['sideimage'];
if ($row['rating'] == 3)
{$rating = "Best";}
if ($row['rating'] == 2)
{$rating = "Better";}
if ($row['rating'] == 1)
{$rating = "Good";}
$bg = ($bg=='#222222' ? '#676767' : '#222222');
echo '<tr bgcolor="' . $bg . '"><td align="left">' . $row['yeast'] . '</td><td><div align="center">' . $rating . '</div></td><td align="left">' . $row['description'] . '</td> <td><a href="' . $row['weblink'] . '" title="Go find">Buy</a></td><td><img src="' . $row['image'] . '" width="100" height="100" alt="Vintners Harvest Yeast" longdesc="' . $row['image'] . '" /></tr>';
如果有人能为我翻译,我将非常感激。 6个小时并且厌倦了。
如果您需要任何其他信息,请与我们联系。
保罗答案 0 :(得分:0)
<?php
$db = new PDO('mysql:host=HOST;dbname=DATABASE', $user, $pass);
$stmt = $db->prepare('
SELECT
yeast,
rating,
description,
weblink,
image,
sideimage
FROM dowdb_yeast_selector
WHERE
fruit = :fruit
ORDER BY
rating DESC
');
$stmt->bindParam(':fruit',$_POST['fruit'],PDO::PARAM_STR,50);
$stmt->execute();
while ($row = $stmt->fetch())
print_r($row);
我想你知道如何操纵$row