Question

我一直在尝试将方法返回Long，但我得到的只是null。有没有办法做到这一点？

interface Clock {
    Long currentTimeMillis();
}

def "stub method returning long"() {
    Clock clock = Mock(Clock)
    clock.currentTimeMillis() >> 1

    when:
    Long currentTime = clock.currentTimeMillis()

    then:
    currentTime == 1
    1 * clock.currentTimeMillis()
}

def "mock method returning longs"() {
    Clock clock = Mock(Clock)
    clock.currentTimeMillis() >>> [1, 2, 3]

    when:
    Long currentTime = clock.currentTimeMillis()

    then:
    currentTime == 1
    1 * clock.currentTimeMillis()
}

在这两个测试中，我都会收到以下错误：

Condition not satisfied:

  currentTime == 1
  |           |
  null        false

Answer 1

当您模拟并记录行为时，应定义如下。

以下是它的工作原理：

@Grab('org.spockframework:spock-core:0.7-groovy-2.0')
@Grab('cglib:cglib-nodep:3.1')

import spock.lang.*


class Test extends Specification {
    def "stub method returning long"() {
        given:
        Clock clock = Mock(Clock)

        when:
        Long currentTime = clock.currentTimeMillis()

        then:
        currentTime == 1
        1 * clock.currentTimeMillis() >> 1
    }

    def "mock method returning longs"() {
        given:
        Clock clock = Mock(Clock)

        when:
        Long currentTime = clock.currentTimeMillis()

        then:
        currentTime == 1
        1 * clock.currentTimeMillis() >>> [1, 2, 3]
    }
}

interface Clock {
    Long currentTimeMillis();
}

如何在Spock中返回Long的stub方法？

1 个答案: