Question

我有一个数据集，我需要将每个数据重命名为＆＃34; KAS＆＃34;对于列中的每个KASARAGOD实例。我需要将该列中的所有内容替换为＆＃34; KAS＆＃34;如果找到实例。

P O, PIN: 671543,KASARAGOD只是KAS

我应该使用什么命令？

示例数据：

G05 G06 G07 G08 G09 G10 address_2
A   A+  A+  A+  A+  A+  KUMBADAJE P O, PIN: 671551, KASARAGOD
A   B   B   B+  A   A   MALLAM P O, PIN: 671542, KASARAGOD
B+  B   B+  A+  C+  B+  KUMBADAJE P O, PIN: 671551, KASARAGOD
B+  B+  B   B+  A   A+  MOVVAR P O, PIN: 671543, KASARAGOD
B   B   B   B+  A+  A+  MOVVAR P O, PIN: 671543, KASARAGOD
A+  A+  A+  A+  A+  A+  MOVVAR P O, PIN: 671543, KASARAGOD
B+  B+  B   A   B+  A   YETHADKA P O, PIN: 671551, KASARAGOD
C   C   C   C   C   A   MOVVAR P O, PIN: 671543, KASARAGOD
A+  A+  A+  A+  A+  A+  MOVVAR P O, PIN: 671543, KASARAGOD

Answer 1

示例数据：

x <- c("(P O, PIN: 671543,RANCHI)", "(P O, PIN: 671543,BLAH)", "(P O, PIN: 67338,RANCITY)", "(P O, PIN: 671543,BBBCHI)")

可以尝试grepl和ifelse

x <- ifelse(grepl("RANCHI", x), "(RAN)", x)
x
## [1] "(RAN)" "(P O, PIN: 671543,BLAH)"   "(P O, PIN: 67338,RANCITY)" "(P O, PIN: 671543,BBBCHI)"

或只是grep（或grepl）

x[grep("RANCHI", x)] <- "(RAN)"
x
## [1] "(RAN)"  "(P O, PIN: 671543,BLAH)"   "(P O, PIN: 67338,RANCITY)" "(P O, PIN: 671543,BBBCHI)"

Answer 2

这会将包含在括号中的RANCHI的每个文本实例替换为(RAN)。

x <- gsub("\\(.*RANCHI.*\\)", "\\(RAN\\)", x)

Answer 3

我的第一个想法是gsub。如果您的数据框名为edu，请尝试

edu$address_2 <- gsub(".*KASARAGOD.*", "KAS", edu$address_2)

这会给你

G05 G06 G07 G08 G09 G10 address_2
  A  A+  A+  A+  A+  A+       KAS
  A   B   B  B+   A   A       KAS
 B+   B  B+  A+  C+  B+       KAS
 B+  B+   B  B+   A  A+       KAS
  B   B   B  B+  A+  A+       KAS
 A+  A+  A+  A+  A+  A+       KAS
 B+  B+   B   A  B+   A       KAS
  C   C   C   C   C   A       KAS
 A+  A+  A+  A+  A+  A+       KAS

用R中的一个字母替换整个字符串

3 个答案: