我想使用Yii框架将调整大小的图像上传到Amazon S3存储桶,但要直接执行 - 无需将原始(未调整大小)图像上传到任何文件夹,Yii,网站或服务器结构中的任何位置。
我使用 ThumbsGen 扩展程序来创建图像的缩略图。如果我在自己的服务器上上传文件,代码可以工作。但是,如果我将图像上传到S3,那么它将不会创建缩略图。
我的代码如下所示:
<?php
Yii::app()->setComponents(array('ThumbsGen' => array(
'class' => 'ext.ThumbsGen.ThumbsGen',
'thumbWidth' => Yii::t('constants', 'SECRETCODE_WIDTH'),
'thumbHeight' => Yii::t('constants', 'SECRETCODE_HEIGHT'),
'baseSourceDir' => Yii::app()->request->s3baseUrl.'/uploads/secretcode/original/',
'baseDestDir' => Yii::app()->request->s3baseUrl. '/uploads/secretcode/thumbs/',
'postFixThumbName' => null,
'nameImages' => array('*'),
'recreate' => false,
)));
class SecretCodeController extends MyController {
public function actionCreate() {
$model = new SecretCode;
$model->scenario = 'create';
if (isset($_POST['SecretCode'])) {
$model->attributes = $_POST['SecretCode'];
$temp = $model->promo_image = CUploadedFile::getInstance($model, 'promo_image');
if ($model->validate()) {
$rnd = rand(1, 1000);
$ext = $model->promo_image->extensionName;
$filename = 'secret_' . Yii::app()->user->app_id . '_' . time() . '_' . $rnd . '.' . $ext; $success = Yii::app()->s3->upload( $temp->tempName , 'uploads/secretcode/original/'.$filename);
if(!$success)
{
$model->addError('promo_image', Yii::t('constants', 'IMAGE_FAILURE'));
} else {
$model->promo_image = $filename; $model->promo_image = $filename;
$fullImgSource = @Yii::app()->s3->getObject(Yii::app()->params->s3bucket_name,"uploads/secretcode/original/".$filename);
list($width, $height, $type, $attr) = getimagesize($fullImgSource->headers['size']);
$dimensions = array();
$dimensions = CommonFunctions :: SetImageDimensions($width, $height,Yii::t('constants', 'SECRETCODE_WIDTH'), Yii::t('constants', 'SECRETCODE_HEIGHT'));
Yii::app()->ThumbsGen->thumbWidth = $dimensions['width'];
Yii::app()->ThumbsGen->thumbHeight = $dimensions['height'];
Yii::app()->ThumbsGen->createThumbnails();
}
if ($model->save()) {
Yii::app()->user->setFlash('success', Yii::t('constants', 'Secret Code')." ". Yii::t('constants', 'ADD_SUCCESS'));
$this->redirect(array('create'));
}
}
}
}
$this->render('create', array(
'model' => $model,
));
}
}
结果,我收到了一条PHP警告:
getimagesize(42368) [<a href='function.getimagesize'>function.getimagesize</a>]: failed to open stream: No such file or directory
我做错了什么?
答案 0 :(得分:1)
getimagesize - 获取图片大小
array getimagesize ( string $filename [, array &$imageinfo ] )
您的代码:
list($width, $height, $type, $attr) = getimagesize($fullImgSource->headers['size']);
$ fullImgSource-&gt; headers ['size'] - 我怀疑它是否存储了图像的文件路径;
试试这个:
list($width, $height, $type, $attr) = $fullImgSource->headers['size'];
或
list($width, $height, $type, $attr) = getimagesize(/*path to image*/);