每个表格(table1& table2)都有自己的DATETIME字段 我试图捕捉两个表中的id并按DATETIME字段对它们进行排序。
示例:
Table 1 Table 2
------------ -------------
id | datetime1 id | table1id | datetime2
------------------------ -----------------------
1 | 2014-09-21 20:31:26 1 | 2 | 2014-09-21 20:31:29
2 | 2014-09-21 20:31:27 2 | 3 | 2014-09-21 20:31:30
3 | 2014-09-21 20:31:28
Table 3
------------
id | user
------------------------
2 | phil
3 | nathalie
我的输出未按此查询正确排序:
SELECT *
FROM (
SELECT
1 AS selection,
table1.id, table1.datetime1,
table2.datetime2
table3.user
FROM Table1
LEFT OUTER JOIN table2
ON table1.id = table2.table1id
LEFT OUTER JOIN table3
ON table1.id = table3.id
UNION ALL
SELECT
2 AS selection,
table1.id, table1.datetime1,
table2.datetime2
table3.user
FROM Table1
INNER JOIN table2
ON table1.id = table2.table1id
INNER JOIN table3
ON table1.id = table3.id
) AS query
ORDER BY table1.datetime1 DESC, table2.datetime2 DESC
所需数据:
来自表2 id:2,1,
从表1 id:3,2,1
所以:2,1,3,2,1
//// EDIT
对于那些可能会遇到漫长而复杂的MySQL请求的人,请在PhpmyAdmin中尝试一下!它会告诉你错误!
////编辑
答案 0 :(得分:3)
您真正需要做的是更仔细地考虑您的架构。考虑将日期时间列命名为相同,然后运行这样的查询 - http://sqlfiddle.com/#!2/a3b4c/7/0
SELECT selection, id, datetimefoo, user FROM (
SELECT
1 AS selection,
table1.id, table1.datetimefoo,
table3.user
FROM table1
LEFT OUTER JOIN table2
ON table1.id = table2.table1id
LEFT OUTER JOIN table3
ON table1.id = table3.id
UNION
SELECT
2 AS selection,
table1.id, table1.datetimefoo,
table3.user
FROM table1
INNER JOIN table2
ON table1.id = table2.table1id
INNER JOIN table3
ON table1.id = table3.id
) AS T2
ORDER BY datetimefoo DESC
在SQL小提琴中,这会产生更接近您正在寻找的结果。我仍然不确定为什么你在第二个问题上需要INNER JOINS - 你没有在这里做任何需要它们的事情。
以下是另一种不需要更改列名的方法,但需要可排序列的别名 - http://sqlfiddle.com/#!2/ec4bc/3/0
SELECT * FROM (
SELECT
1 AS selection,
table1.id, table1.datetimefoo AS sort_date, -- alias on first table's date
table2.datetimebar,
table3.user
FROM table1
LEFT OUTER JOIN table2
ON table1.id = table2.table1id
LEFT OUTER JOIN table3
ON table1.id = table3.id
UNION
SELECT
2 AS selection,
table1.id, table1.datetimefoo,
table2.datetimebar AS sort_date, -- alias on second table's date
table3.user
FROM table1
INNER JOIN table2
ON table1.id = table2.table1id
INNER JOIN table3
ON table1.id = table3.id
) AS T2
ORDER BY sort_date DESC
答案 1 :(得分:2)
我相信你的任务过于复杂:
SELECT *
FROM (
SELECT 1 AS selection, table1.id as id, table1.datetime1 as date FROM Table1
UNION ALL
SELECT 2 AS selection, table2.id as id, table2.datetime2 as date FROM Table2
) AS query
ORDER BY date DESC